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svetoff [14.1K]

3 years ago

12

The length of a rectangle is twice the width. The area of the rectangle 88 is square units. Notice that you can divide the recta

ngle into two squares with equal area. How can you estimate the side length of each square? Estimate the length and width of the rectangle.

1 answer:

astra-53 [7]3 years ago

5 0

Answer:

Width of the rectangle = 6.325 units

Length of the rectangle = 12.65 units

Side length of the square the 6.325 units.

Step-by-step explanation:

The length of a rectangle is twice the width. The area of the rectangle is 80 square units.

The area of the rectangle = Length × Width

Length = 2W

80 square units = 2W × W

80 = 2W²

W² = 80/2

W² = 40

W = √40

Width of the rectangle = 6.3245553203 units

Approximately = 6.325 units

Length = 2 × Width

= 2 × 6.325

= 12.65 units

• Notice that you can divide the rectangle into two squares with equal area. How can you estimate the side length of each square?

We you divide a rectangle into 2 squares,

The length is divided into two.

Hence, the length of the rectangle = 12.65 units

12.65 units ÷ 2 = 6.325 units.

Hence, the side length of the square the 6.325 units.

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In this right triangle, what is the length of the hypotenuse?

Phantasy [73]

Answer:

it is a^2 +b^2 =c^2

Step-by-step explanation:

you square the width and the length and add them and you get the hypotenuse

then you find the root of the hypotenuse and that is our answer

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2 years ago

Tom put 18 gallons of mid grade gas in his truck and filled up his empty five gallon gas tank with regular gas for his lawn mowe

LuckyWell [14K]

Answer:

Mid grade gas per gallon = $2.67

Regular gas per gallon = $2.37

Step-by-step explanation:

Let, x= mid grade gas, y=regular gas.

So, for 18 gallons of mid grade gas and 5 gallon of regular gas at $59.91, it can be expressed as,

$18x+5y=59.91$ ------------------(equation 1)

for 14 gallon of mid grade gas and 1 gallon of regular gas at 39.75, it can be expressed as,

$14x+y=39.75$ -------------------(equation 2)

$y=39.75-14x$ -------------------(equation 3)

Now substituting the value of y from (equation 3) in (equation 1) we get,

$18x+5y=59.91$

$18x+5(39.75-14x)=59.91$

$18x+198.75-70x=59.91$

$52x=198.75-59.91$

$52x=138.84$

$x=\frac{138.84}{52}$

$x=2.67$ -------------------------(equation 4)

Now substituting value of x from (equation 4) in (equation 3) we get,

$y=39.75-14x$

$y=39.75-(14\times2.67)$

$y=39.75-37.38$

$y=2.37$

Therefore price per gallon of mid grade gas is x = $2.67, and price per gallon of regular gas y = $2.37.

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3 years ago

Kite ABCD has a longer diagonal AC with a length of 20in and a shorter diagonal BD with a length of 15in. The diagonals intersec

erma4kov [3.2K]

That is not enough information.
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6 0

4 years ago

Electric charge is distributed over the disk x2 + y2 ≤ 16 so that the charge density at (x, y) is rho(x, y) = 2x + 2y + 2x2 + 2y

professor190 [17]

Answer:

Required total charge is $256\pi$ coulombs per square meter.

Step-by-step explanation:

Given electric charge is dristributed over the disk,

$x^2=y^2\leq 16$ so that the charge density at (x,y) is,

$\rho (x,y)=2x+2y+2x^2+2y^2$

To find total charge on the disk let Q be the total charge and $x=r\cos\theta,y=r\sin\theta$ so that,

$Q={\int\int}_Q\rho(x,y) dA$ where A is the surface of disk.

$=\int_{0}^{2\pi}\int_{0}^{4}(2x+2y+2x^2+2y^2)dA$

$=\int_{0}^{2\pi}\int_{0}^{4}(2r\cos\theta+2r\sin\theta+2r^2 \cos^{2}\theta+2r^2\sin^2\theta)rdrd\theta$

$=2\int_{0}^{2\pi}\int_{0}^{4}r^2(\cos\theta+\sin\theta)drd\theta+2\int_{0}^{2\pi}\int_{0}^{4}r^3drd\theta$

$=\frac{2}{3}\int_{0}^{2\pi}(\sin\theta+\cos\theta)\Big[r^3\Big]_{0}^{4}d\theta+2\int_{0}^{2\pi}\Big[\frac{r^4}{4}\Big]d\theta$

$=\frac{128}{3}\int_{0}^{2\pi}(\sin\theta+\cos\theta)d\theta+128\int_{0}^{2\pi}d\theta$

$=\frac{128}{3}\Big[\sin\theta-\cos\theta\Big]_{0}^{2\pi}+128\times 2\pi$

$=\frac{128}{3}\Big[\sin 2\pi-\cos 2\pi-\sin 0+\cos 0\Big]+256\pi$

$=256\pi$

Hence total charge is $256\pi$ coulombs per square meter.

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3 years ago

Can somebody please help answer this word problem using grass method? And showing how u get the answer thanks!!!

siniylev [52]

Answer:

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Step-by-step explanation:

Given Height of Dorsal Fin = 1/6 of Length of whale Sculpture,

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Height of Dorsal fin on scuplture = $(\frac{1}{6})(1\frac{1}{2} )\\$

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5 0

2 years ago