A fish tank is in the shape of a cube. Its volume is 125 ft 3. what is the area of one face of the tank

Which expression is equivalent to the following complex fraction? StartFraction 1 Over x EndFraction minus StartFraction 1 Over

Darina [25.2K]

Answer:

$\frac{y-x}{x+y}$

Step-by-step explanation:

We are given that fraction

$\frac{\frac{1}{x}-\frac{1}{y}}{\frac{1}{x}+\frac{1}{y}}$

We have to find the expression which is equivalent to given fraction .

$\frac{1}{x}-\frac{1}{y}=\frac{y-x}{xy}$

$\frac{1}{x}+\frac{1}{y}=\frac{x+y}{xy}$

Substitute the values then, we get

$\frac{\frac{y-x}{xy}}{\frac{y+x}{xy}}$

We know that

$\frac{\frac{a}{b}}{\frac{x}{y}}=\frac{a}{b}\times \frac{y}{x}$

Using the property then, we get

$\frac{y-x}{xy}\times \frac{xy}{x+y}$

$\frac{y-x}{x+y}$

This is required expression which is equivalent to given expression.

6 0

3 years ago

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2(x+3)=x-4<br> please help me <3

vovikov84 [41]

2(x + 3) = x - 4

distribute

2x + 6 = x - 4

either subtract 6 from both sides or add 4. i will be subtracting 6.

2x = x - 10

subtract x from both sides

x = -10

4 0

2 years ago

Your parents have a realized income of $1,046.78/every 2 weeks. How much should the monthly housing expense budget be to stay wi

IgorLugansk [536]

Answer with explanation:

Income earned by my parents in every two weeks = $ 1046.78

In two weeks there are 14 days, so income earned by my parents in 1 day

$=\frac{1046.78}{14}\\\\74.77$

Income of my parents after a month, if there are 30 days in a month = $74.77 × 30= $ 2243.10

We, will use , $\frac{28}{36}$ rule here , which states that , 28% of monthly income of my parents, should be used for monthly housing expenses ,and 36% of gross monthly income should be used for debt purposes.

28% of $2243.78

$=\frac{28}{100}*2243.78\\\\=\frac{62825.84}{100}\\\\=628.2584$

= $ 628.26 (Approx)

So,my parents, monthly housing expense should not exceed ≥ $ 628.26

8 0

3 years ago

In a board game, you must roll two 6-sided number cubes. You can only start the game if you roll a 3 on at least one of the numb

NeTakaya

B is 2 out of 12

c is if you were talking probability then you would have put down one out of 6 because there is one 3 out of 6 sides but i believe i would expect to see two times 34 because it is two time the dice and it gives you the capability to earn three twice as much so you should see it at least 68 times

HOPE THIS HELPS

im not clear on a tho

6 0

2 years ago

Find the shaded sector and the length of the arc. Round to the nearest hundredth.

Dovator [93]

Answer:

Step-by-step explanation:

I'll show you how to do the first one; the other are exactly the same, so pay attention.

The formula for arc length is

$AL=\frac{\theta}{360}*2\pi r$ where θ is the central angle's measure. It just so happens that the measure of the central angle is the same as the measure of the arc it intercepts. Our arc shows a measure of 40°; this measure is NOT the same as the length. Measures are in degrees while length is in inches, or cm, or meters, etc. Going off that info, our central angle measures 40°. Filling in the formula and using 3.1415 for π:

$AL=\frac{40}{360}*2(3.1415)(3)$ . I'm going to reduce that fraction a bit (and I'll use the same reduction in the Area of a sector coming up next):

$AL=\frac{1}{9}*2(3.1415)(3)$ which makes

AL = 2.09 units. Now for Area of the Sector. The formula is almost identical, but instead uses the idea that the area of a circle is πr²:

$A_s=\frac{\theta}{360}*\pi r^2$ where θ is, again, the measure of the central angle (which is the same as the measure of the arc it intercepts). Filling in:

$A_s=\frac{1}{9}*(3.1415)(3)^2$ which simplifies a bit to

$A_s=\frac{1}{9}*(3.1415)(9)$ . As you can see, the 9's cancel each other out, leaving you with

$A_s=3.14$ units²

7 0

2 years ago

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