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3 years ago

Which trigonometric function would you use to solve the problem?

Mathematics

1 answer:

umka21 [38]3 years ago

3 0

you would use tan or cot

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I need help asap :):)):):

Ksju [112]

Answer:

$43.20

Step-by-step explanation:

Subtract the tax to find the actual sale price then multiply by 4. 12-1.20=10.80.... 10.80*4=43.30

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3 years ago

Read 2 more answers

Please help, me I just need to know how to set it up the 2 equation on both.

Ronch [10]

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3 years ago

In the story of factory fire marshall william beer stunned new yorker by declaring

Artist 52 [7]

He declared that he could show the people "150 loft buildings far worse than" the Asch Building.

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3 years ago

Suppose that the Celsius temperature at the point (x, y) in the xy-plane is T(x, y) = x sin 2y and that distance in the xy-plane

liraira [26]

Missing information:

How fast is the temperature experienced by the particle changing in degrees Celsius per meter at the point

$P = (\frac{1}{2}, \frac{\sqrt 3}{2})$

Answer:

$Rate = 0.935042^\circ /cm$

Step-by-step explanation:

Given

$P = (\frac{1}{2}, \frac{\sqrt 3}{2})$

$T(x,y) =x\sin2y$

$r = 1m$

$v = 2m/s$

Express the given point P as a unit tangent vector:

$P = (\frac{1}{2}, \frac{\sqrt 3}{2})$

$u = \frac{\sqrt 3}{2}i - \frac{1}{2}j$

Next, find the gradient of P and T using: $\triangle T = \nabla T * u$

Where

$\nabla T|_{(\frac{1}{2}, \frac{\sqrt 3}{2})} = (sin \sqrt 3)i + (cos \sqrt 3)j$

So: the gradient becomes:

$\triangle T = \nabla T * u$

$\triangle T = [(sin \sqrt 3)i + (cos \sqrt 3)j] * [\frac{\sqrt 3}{2}i - \frac{1}{2}j]$

By vector multiplication, we have:

$\triangle T = (sin \sqrt 3)* \frac{\sqrt 3}{2} - (cos \sqrt 3) \frac{1}{2}$

$\triangle T = 0.9870 * 0.8660 - (-0.1606 * 0.5)$

$\triangle T = 0.9870 * 0.8660 +0.1606 * 0.5$

$\triangle T = 0.935042$

Hence, the rate is:

$Rate = \triangle T = 0.935042^\circ /cm$

3 0

2 years ago

Eva has £6.05 in her moneybox.

PIT_PIT [208]

Answer:

11 of 20p, 22 of 10p and 33 of 5p

Step-by-step explanation:

Eva has 20p, 10p and 5p coins, total of £6.05 = 605p

Let 20p=x, 10p=y, 5p=z

Then:

20x + 10y + 5z = 605
y : x = 2 : 1 ⇒ x= y/2
y : z = 2 : 3 ⇒ z= 3y/2

Rewriting the first equation considering next two:

10y + 10y + 7.5y = 605
27.5y = 605
y= 605/27.5
y= 22
x= y/2 = 22/2 = 11
z = 3y/2 = 3*11 = 33

Answer: 11 of 20p coins, 22 of 10p coins and 33 of 5p coins

3 0

3 years ago