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dybincka [34]
3 years ago
9

I’m on a test so I need help

Mathematics
1 answer:
sladkih [1.3K]3 years ago
4 0
The answer is 2 y2 -9
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The length of an 8000 square foot rectangular gymnasium is 20 feet greater than its width.
Svetach [21]

Answer: 80 feet.

Step-by-step explanation:

You can calculate the width using two equations and solving for the side lengths.

L * W = 8000

L = 20 + W

You can then substitute the L in the first equation for the L in the second equation:

(20+W)*W = 8000

W^2 + 20W - 8000 = 0

Now, you can factor this equation to solve it:

(W + 100)(W-80) = 0

Your solutions for W are -100 and 80. Considering the width of a rectangle cannot be negative, the only possible solution is 80 feet, which makes your length 100 feet.

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D would be the true statement
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Your answer would be \sqrt{19}

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Can someone help please I need this done in 20 minutes and no links I have been getting them all day so please help me with this
Natasha2012 [34]
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3.3mi
4.8+7(3)=8+21=29mi
5.yes, she hikes continuously so distance can be fractional parts of a mile
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