3 years ago

I’m on a test so I need help

Mathematics

1 answer:

sladkih [1.3K]3 years ago

4 0

The answer is 2 y2 -9

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3 years ago

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12p + 7 > 139 greater or less than

bazaltina [42]

Answer:

$\Huge \boxed{p>11}$

Step-by-step explanation:

First, subtract by 7 both sides of equation.

$\displaystyle 12p+7-7>139-7$

Solve.

$\displaystyle 139-7=132$

$12p>132$

Then, divide by 12 both sides of equation.

$\displaystyle \frac{12p}{12}=\frac{132}{12}$

Solve to find the answer.

$\displaystyle 132\div12=11$

$\huge \boxed{p>11}$ , which is our answer.

3 0

3 years ago

He table shows the solution to the equation |2x − 5| − 2 = 3:

ozzi

The solution is completely correct, as putting 5 or 0 in the formula again will make it true.

$|2(0)-5|=5$
$|-5|=5$
$5=5$

$|2(5)-5|=5$
$|10-5|=5$
$5=5$

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3 years ago

There are five consecutive even integers. The sum of the first two is thirty-six less than the sum of the last three numbers. Wh

Norma-Jean [14]

5 consecutive even integers: 2n, 2n+2, 2n+4, 2n+6, 2n+8 for any integer n The sum of the two smallest of five consecutive even integers is 50 less than the sum of the other three integers: 2n + 2n+2 = 2n+4 + 2n+6 + 2n+8 - 504n + 2 = 6n -3234 = 2nn = 17 <span>The smallest integer in our sequence is 2n = 2*17 = 34</span> Check:2n + 2n+2 = 2n+4 + 2n+6 + 2n+8 - 5034 + 36 = 38 + 40 + 42 - 5070 = 120 - 5070 = 70

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hodyreva [135]

Step-by-step explanation:

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3 years ago