I’m on a test so I need help

Help please!!!!!!!! It’s pre cal

tino4ka555 [31]

Answer:

No, the inverse function does not pass the vertical line test.

Step-by-step explanation:

Remember that $h(x)=y$ . To find the inverse of our function we are going to invert x and y and solve for y:

$h(x)=x^2+3$

$y=x^2+3$

$x=y^2+3$

$x-3=y^2$

$y=\pm\sqrt{x-3}$

$h^{-1}(x)=\pm\sqrt{x-3}$

Now we can graph our function an perform the vertical line test (check the attached picture).

Remember that the vertical line test is a visual way of determine if a relation is a function. A relation is a function if and only if it only has one value of y for each value of x. In other words, a relation is a function if a vertical line only intercepts the graph of the function once.

As you can see in the picture, the vertical line x = 15 intercepts the function twice, so the inverse function h(x) is not a function.

We can conclude that the correct answer is: No, the inverse function does not pass the vertical line test.

6 0

3 years ago

Read 2 more answers

Evaluate e^-2to one decimal place.

aleksklad [387]

$\bf ~~~~~~~~~~~~\textit{negative exponents}\\\\
a^{-n} \implies \cfrac{1}{a^n}
\qquad \qquad
\cfrac{1}{a^n}\implies a^{-n}
\qquad \qquad 
a^n\implies \cfrac{1}{a^{-n}}\\\\
-------------------------------\\\\
e^{-2}\implies \cfrac{1}{e^2}$

plug that in your calculator, yes, your calculator has an [ e ], button for the Euler's constant.

4 0

3 years ago

Suppose that an airline quotes a flight time of 128 minutes between two cities. Furthermore, suppose that historical flight reco

ANTONII [103]

Answer:

(a) The probability density function of X is:

$f_{X}(x)=\frac{1}{b-a};\ a$