Question

In a class of 147 students, 95 are taking math(m), 75 are taking science (s), 52 are taking both math and science. What is the probability of randomly choosing a student who is taking neither math nor science? Round your answer to the nearest tenth

Answer 1

Subtract 52 from m, s, and the total amount of students.. 52 is the amount of students that would take both math and science. m now equals 43, s now equals 23, and the total students remaining is 95.

Since the criteria wants you to exclude students that take math or science, add m and s together. 

$43 + 23 = 66$

This is the total amount of students that take math or science.

To find the probability of picking a student that doesn't take math or science, subtract 66 from the total amount of students. 

$95 - 66 = 29$

Take this amount and divide by the total amount of students again.

$\frac{29}{95} = 0.3052$

Convert the decimal into a percentage.

$0.3052 = 30.52$ %

There is a 30.52% chance of picking a student that doesn't take math nor science.