Because we cannot subtract or add up constants and variables, we simply move the same variable term to the same side and constant term to the same constant side.
Substitute d = -11 in the equation.
The equation is true for d = -11.
<h3><u>Answer</u></h3><u></u>
The baker bought 7 gala apples, and 12 granny smiths apples
<em><u>Solution:</u></em>
Let "x" be the number of gala apples bought
Let "y" be the number of granny smith apples bought
Cost of 1 gala apple = $ 0.30
Cost of 1 granny smith apple = $ 0.25
<em><u>A baker buys 19 apples of two different varieties to make pies</u></em>
Therefore,
number of gala apples bought + number of granny smith apples bought = 19
x + y = 19 --------- eqn 1
<em><u>The total cost of the apples is $5.10</u></em>
Therefore, we can frame a equation as:
number of gala apples bought x Cost of 1 gala apple + number of granny smith apples bought x Cost of 1 granny smith apple = 5.10
0.3x + 0.25y = 5.1 -------- eqn 2
<em><u>Let us solve eqn 1 and eqn 2</u></em>
From eqn 1,
x = 19 - y ---------- eqn 3
<em><u>Substitute eqn 3 in eqn 2</u></em>
0.3(19 - y) + 0.25y = 5.1
5.7 - 0.3y + 0.25y = 5.1
5.7 - 0.05y = 5.1
0.05y = 5.7 - 5.1
0.05y = 0.6
y = 12
<em><u>Substitute y = 12 in eqn 3</u></em>
x = 19 - 12
x = 7
Thus the baker bought 7 gala apples, and 12 granny smiths apples