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disa [49]
3 years ago
13

Formulate the situation as a linear programming problem by identifying the variables, the objective function, and the constraint

s. Be sure to state clearly the meaning of each variable. Determine whether a solution exists, and if it does, find it. State your final answer in terms of the original question. A rancher raises goats and llamas on his 400-acre ranch. Each goat needs 2 acres of land and requires $100 of veterinary care per year, and each llama needs 5 acres of land and requires $80 of veterinary care per year. The rancher can afford no more than $13,200 for veterinary care this year. If the expected profit is $84 for each goat and $126 for each llama, how many of each animal should he raise to obtain the greatest possible profit? The rancher should raise goats and llamas for a maximum profit of $________

Mathematics
1 answer:
abruzzese [7]3 years ago
3 0

Answer:

zero goats and 120 Ilamas to get profit of $15,120

Step-by-step explanation:

Goats: G

Ilamas: l

Explicit constraints:

2G + 5l ≤ 400

100G+ 80l≤ 13,200

Implicit constraints

G≥0

I≥0

P= 84G+ 126l

See attachment for optimal area

substituting coordinats of optimal region in profit equation to get profit

When G= 132, l=0

P=84(132) + 126(0)

P=11,088

When G=0, l=120

P=84(0)+ 126(120)

P = 15120

When G= 100, l=40

P=84(100)+126(40)

P=13440

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Find the value of x such that 365 based seven + 43 based x = 217 based 10.
Pepsi [2]

We need to find the base x in the following equation:

365_7+43_x=217_{10}

First, lets convert 365 from base 7 to base 10. This is given by

365_7=3\times7^2+6\times7^1+5\times7^0

where the upperindex denotes the position of eah number. This gives

\begin{gathered} 365_7=3\times49+6\times7+5\times1 \\ 365_7=147+42+5 \\ 365_7=194_{10} \end{gathered}

that is, 365 based 7 is equal to 194 bases 10.

Now, lets do the same for 43 based x. Lets convert 43 based x to base 10:

43_x=4\times x^1+3\times x^0

where again, the superindex 0 and 1 denote the position 0 and 1 in the number 43. This gives

43_x=(4x+3)_{10}

Now, we have all number in base 10. Then, our first equation can be written in base 10 as

194_{10}+(4x+3)_{10}=217_{10}

For simplicity, we can omit the 10 and get

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so, we can solve this equation for x. By combining similar terms. we have

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and by moving 197 to the right hand side, we obtain

\begin{gathered} 4x=217-197 \\ 4x=20 \end{gathered}

Finally, we get

\begin{gathered} x=\frac{20}{4} \\ x=5 \end{gathered}

Therefore, the solution is x=5

8 0
1 year ago
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