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3 years ago

-4(8n-3)=84 how do i do this

1 answer:

7 0

Best to ask, "How do I solve this equation for n?"

1. Div. both sides by -4, along the way to isolating 8n-3 and then n:
8n-3 = -21
2. Add 3 to both sides: 8n = -18
3. Solve for n: n = -18/8 = -9/4 (answer)

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Approximate the square root to the nearest integer.<br> 37

REY [17]

6.083 would be the answer

8 0

3 years ago

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find four solutions for the following linear equations your answer must include at least two positive numbers for X and at least

sattari [20]

9514 1404 393

Answer:

(-18, 14), (-9, 9), (9, -1), (18, -6)

Step-by-step explanation:

Since there is a 9 in the denominator of the coefficient of x, we will get integer solutions only if x is a multiple of 9. Suitable values meeting the problem requirements are x ∈ {-18, -9, 9, 18}. Then the corresponding values of y are ...

y = -5/9(-18) +4 = 10 +4 = 14

y = -5/9(-9) +4 = 5 +4 = 9

y = -5/9(9) +4 = -5 +4 = -1

y = -5/9(18) +4 = -10 +4 = -6

The four solutions we have found are ...

(-18, 14), (-9, 9), (9, -1), (18, -6)

4 0

2 years ago

What is the solution set for 2x+5y>-1 and 4x-3<-3?

bekas [8.4K]

PROBLEM ONE

•

Solving for x in 2x + 5y > -1.

•

Step 1 ) Subtract 5y from both sides.

2x + 5y > -1

2x + 5y - 5y > -1 - 5y

2x > -1 - 5y

Step 2 ) Divide both sides by 2.

2x > -1 - 5y

$\displaystyle\frac{2x}{2} > \displaystyle\frac{-1 - 5y}{2}$

$\displaystyle\ x > \frac{-1 - 5y}{2}$

So, the solution for x in 2x + 5y > -1 is...

$\displaystyle\ x > \frac{-1 - 5y}{2}$

•

Solving for y in 2x + 5y > -1.

•

Step 1 ) Subtract 2x from both sides.

2x + 5y > -1

2x - 2x + 5y > -1 - 2x

5y > -1 - 1x

Step 2 ) Divide both sides by 5.

5y > -1 - 1x

$\displaystyle\frac{5x}{5} > \frac{-1 -1x}{5}$

$\displaystyle\ x > \frac{-1 -1x}{5}$

So, the solution for y in 2x + 5y > -1 is...

$\displaystyle\ x > \frac{-1 -1x}{5}$

•

PROBLEM TWO

•

Solving for x in 4x - 3 < -3.

•

Step 1 ) Subtract 3 from both sides.

4x - 3 < -3

4x -3 - 3 < -3 - 3

4x < 0

Step 2 ) Divide both sides by x.

4x < 0

$\displaystyle\frac{4x}{4}$

x < 0

So, the solution for x in 4x - 3 < -3 is...

x < 0

•

- <em>Marlon Nunez</em>

7 0

2 years ago

Solve using quadratic equations

olasank [31]

4x² - 9x² + 5 = 0
4x² - 4x - 5x + 5 = 0
4x(x - 1) - 5(x - 1) = 0
(4x - 5)(x - 1) = 0

Set each binomial equal to zero.

4x - 5 = 0
4x = 0 + 5
4x = 5
x = 5/4

x - 1 = 0
x = 0 + 1
x = 1

Your solutions are x = 1, 5/4

7 0

3 years ago

DOSE EDENUITY SUCK? I WANA KNOW!

nadya68 [22]

Answer:

If it involves math then yea

Step-by-step explanation:

trust me bro

6 0

3 years ago

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