A. 
To find greater than or smaller than relation, we multiply the terms like (numerator of L.H.S with denominator of R.H.S and put the value on the left side. Then multiply the denominator of L.H.S with numerator of R.H.S and put the value on right side. Now compare the digits.)
So, solving A, we get 810<209 ... This is false
B. 
= 238>589 ..... This is false
C. 
= 496>780 .... This is false
D. 
= 420<660 ..... This is true
Hence, option D is true.
Add the numbers they equal 30 then u divide 30 by 2 since it’s an odd number and you get 15. so 15 is your answer
The answer is B. There can not be any alike "x" inputs.
Answer:
1. 15 - 5n where n>=1
2. n² where n>=1
Step-by-step explanation:
1. {10, 5, 0, -5, -10} is an Arithmetic Progression
nth term is a + (n - 1)d
where a = first term, n= nth term, d= common difference.
a = 10, d = -5 (5-10, 0-5, -5-0, -10-(-5))
Therefore, nth(General) term of the sequence:
= 10 + (n - 1)-5
= 10 + (-5n) + 5
= 10 + 5 - 5n
= 15 - 5n
Test:
if n = 1; 15 - 5(1) = 10
if n = 2; 15 - 5(2) = 5
if n = 3; 15 - 5(3) = 0 and so on.
2. {1, 4, 9, 16, 25}
The general term of the sequence is n²
Test:
if n = 1; 1² = 1
if n = 2; 2² = 4
if n = 3; 3² = 9 and so on.
