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Natalija [7]
1 year ago
11

Brett writes a number that is the same distance from O as TO 6on a number line, but in the opposite direction. Whatnumber did Br

ett write? Explain how you know.
Mathematics
1 answer:
Gennadij [26K]1 year ago
4 0

since the number is going on the opposite it must be a negative integrer.

and since the number was 6 units away from 0, it should be the half point between the points.

number = 3

since it is going in the oppsoite direction it should be -3

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Answers: D for it represents the diameter and A for represents the radius
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What are 2 ways to solve the problem 9×1×5 = ?
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3 years ago
Data collected at Toronto Pearson International Airport suggests that an exponential distribution with mean value 2725hours is a
Ivan

Answer:

a) What is the probability that the duration of a particular rainfall event at this location is at least 2 hours?

We want this probability"

P(X >2) = 1-P(X\leq 2) = 1-(1- e^{-0.367 *2})=e^{-0.367 *2}= 0.48

At most 3 hours?

P(X \leq 3) = F(3) = 1-e^{-0.367*3}= 1-0.333 =0.667

b) What is the probability that rainfall duration exceeds the mean value by more than 2 standard deviations?

P(X > 2.725 + 2*5.540) = P(X>13.62) = 1-P(X

What is the probability that it is less than the mean value by more than one standard deviation?

P(X

Step-by-step explanation:

Previous concepts

The exponential distribution is "the probability distribution of the time between events in a Poisson process (a process in which events occur continuously and independently at a constant average rate). It is a particular case of the gamma distribution". The probability density function is given by:

P(X=x)=\lambda e^{-\lambda x}

The cumulative distribution for this function is given by:

F(X) = 1- e^{-\lambda x}, x\ geq 0

We know the value for the mean on this case we have that :

mean = \frac{1}{\lambda}

\lambda = \frac{1}{Mean}= \frac{1}{2.725}=0.367

Solution to the problem

Part a

What is the probability that the duration of a particular rainfall event at this location is at least 2 hours?

We want this probability"

P(X >2) = 1-P(X\leq 2) = 1-(1- e^{-0.367 *2})=e^{-0.367 *2}= 0.48

At most 3 hours?

P(X \leq 3) = F(3) = 1-e^{-0.367*3}= 1-0.333 =0.667

Part b

What is the probability that rainfall duration exceeds the mean value by more than 2 standard deviations?

The variance for the esponential distribution is given by: Var(X) =\frac{1}{\lambda^2}

And the deviation would be:

Sd(X) = \frac{1}{\lambda}= \frac{1}{0.367}= 2.725

And the mean is given by Mean = 2.725

Two deviations correspond to 5.540, so we want this probability:

P(X > 2.725 + 2*5.540) = P(X>13.62) = 1-P(X

What is the probability that it is less than the mean value by more than one standard deviation?

For this case we want this probablity:

P(X

8 0
3 years ago
Blake is 7 years older than Heather. In 7 years the sum of their ages will be 55. How old is Blake now?
Andreas93 [3]

Answer:

24 years old

Step-by-step explanation:

Let the age of Blake be x and the age of Heather by y then...

x=7+y

7+x+7+y=55

Notice we are adding additional 7s because the question states "in 7 years"

Simplify the second equation...

7+x+7+y=55

14+x+y=55

Subtract 21 from both sides

x+y=41

Solve using substitution (substitute 7+y for x since x = 7+y)

7+y+y=41

Combine like terms

2y+7=41

Subtract 7 from both sides

2y=34

Divide both sides by 2

y=17

x=7+17=24

Blake is 24 years old now

4 0
2 years ago
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