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Ad libitum [116K]
3 years ago
11

Which equation does the graph of the systems of equations solve? quadratic graph opening down and quadratic graph opening up. Th

ey intersect at negative 4, 0 and negative 3, negative 1.
x2 − 2x + 8 = x2 − 8x − 16
x2 + 6x + 8 = −x2 − 8x − 16
−x2 − 2x + 8 = 2x2 − 8x − 16
−x2 − 2x + 8 = 2x2 − 8x + 16

Mathematics
1 answer:
Ghella [55]3 years ago
5 0
The quadratics of the 2nd choice are the only ones that go through both points (-4, 0) and (-3, -1).

x² +6x +8 = -x² -8x -16

_____
The quadratic with those two points as solution will be of the form
.. a(x +4)(x +3) = 0
.. a(x^2 +7x +12) = 0
When you subtract one side or the other to put the equation in this form, only the 2nd selection matches:
.. 2(x^2 +7x +12) = 0

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3. Consider the sequence,-8, -5, -2, 1, ...
Naddik [55]

Answer:

a) a_n=3\,n-11

b) a_{20}=49

c) term number 17 is the one that gives a value of 40

Step-by-step explanation:

a)

The sequence seems to be arithmetic, and with common difference d = 3.

Notice that when you add 3 units to the first term (-80, you get :

-8 + 3 = -5

and then -5 + 3 = -2 which is the third term.

Then, we can use the general form for the nth term of an arithmetic sequence to find its simplified form:

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That in our case would give:

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b)

Therefore, the term number 20 can be calculated from it:

a_{20}=3\,(20)-11=60-11=49

c) in order to find which term renders 20, we use the general form we found in step a):

a_n=3\,n-11\\40=3\,n-11\\40+11=3\,n\\51=3\,n\\n=\frac{51}{3} =17

so term number 17 is the one that renders a value of 40

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3 years ago
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