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vodomira [7]
3 years ago
10

2. In a school of 320 students, 85 students are in the band, 200 students are on sports teams, and 60 students

Mathematics
1 answer:
Alja [10]3 years ago
8 0

Answer:

<u>60</u> students are involved in either band or sports.

<u>95</u> students  are not involved in either sports or band.

Step-by-step explanation:

Given:

In a school of 320 students, 85 students are in the band, 200 students are on sports teams, and 60 students  participate in both activities.

Now, to find the students  are involved in either sports or band. And students who are not involved in either sports or band.

<em>Total number of students</em> = 320.

Number of students in the band = 85.

Number of students in the sports team = 200.

Number of students participate in both activities = 60.

Thus, 60 students are involved in either band or sports.

So, the number of students in the band adding number of students in the sports team we get:

200 + 85 = 285.

Then, to subtract the number of students participate in both activities we get:

285 - 60 = 225.

<em>Thus, the remaining students are </em>= 225.

Now, to get the students  who are not involved in either sports or band we subtract the total number of students from the remaining students:

320-225

=95.

Therefore, 60 students are not involved in either band or sports. 95 students  are not involved in either sports or band.

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Hey there!

In order to solve this problem, you'll look at (x⁴)(3x³ – 2) first. You need to multiply 4x by both numbers in the binomial to get the distributed version that you'll use later on. 

(x⁴)(3x³) = 3x⁷
(x⁴)(–2) = –2x⁴

Now, your problem is (3x⁷ – 2x⁴)(4x² <span>+ 5x). You will complete the distributing by multiplying the first term of the first binomial by both terms of the second binomial, then repeating this with the second term. You'll then want to add or subtract any repeated terms to combine them, if applicable. Remember that to multiply exponents together, all you need to do is add the numbers. x is the same as x</span>¹.<span>

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7 0
3 years ago
A rectangle has a length of 19 in and a height of 11 in. Another rectangle has a length of 95
scoundrel [369]

Answer:

Option D. No,they are not similar because their side lengths are not proportional.

Step-by-step explanation:

we know that

If two figures are similar, then the ratio of its corresponding sides is proportional and its corresponding angles are congruent

In this problem If the rectangles are similar

then

The ratio of its corresponding lengths must be equal to the ratio of its corresponding heights

<u><em>Verify</em></u>

\frac{95}{19}=\frac{6.5}{11}\\\\95*11=19*6.5\\\\1,045\neq123.5

therefore

The rectangles are not similar because their side lengths are not proportional.

4 0
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5v+8=93

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v=17
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