2. In a school of 320 students, 85 students are in the band, 200 students are on sports teams, and 60 students
1 answer:
Answer:
<u>60</u> students are involved in either band or sports.
<u>95</u> students are not involved in either sports or band.
Step-by-step explanation:
Given:
In a school of 320 students, 85 students are in the band, 200 students are on sports teams, and 60 students participate in both activities.
Now, to find the students are involved in either sports or band. And students who are not involved in either sports or band.
<em>Total number of students</em> = 320.
Number of students in the band = 85.
Number of students in the sports team = 200.
Number of students participate in both activities = 60.
Thus, 60 students are involved in either band or sports.
So, the number of students in the band adding number of students in the sports team we get:
200 + 85 = 285.
Then, to subtract the number of students participate in both activities we get:
285 - 60 = 225.
<em>Thus, the remaining students are </em>= 225.
Now, to get the students who are not involved in either sports or band we subtract the total number of students from the remaining students:
Therefore, 60 students are not involved in either band or sports. 95 students are not involved in either sports or band.
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Answer:
1.7 × 10⁻⁴
Step-by-step explanation:
The question relates to a two sample z-test for the comparison between the means of the two samples
The null hypothesis is H₀: μ₁ ≤ μ₂
The alternative hypothesis is Hₐ: μ₁ > μ₂
Where;
= 13.5
= 12
σ₁ = 2.5
σ₂ = 1.5
We set our α level at 0.05
Therefore, our critical z = ± 1.96
For n₁ = n₂ = 23, we have;
We reject the null hypothesis at α = 0.05, as our z-value, 3.5969 is larger than the critical z, 1.96 or mathematically, since 3.5969 > 1.96
Therefore, there is enough statistical evidence to suggest that Alyse time is larger than Jocelyn in a 1 mile race on a randomly select day and the probability that Alyse has a larger time than Jocelyn is 0.99983
Therefore;
The probability that Alyse has a smaller time than Jocelyn is 1 - 0.99983 = 0.00017 = 1.7 × 10⁻⁴.