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Volgvan
3 years ago
7

What are the 5s in 4,557

Mathematics
2 answers:
pentagon [3]3 years ago
6 0
The 5's in 4,557 are 500 and 50.
elena-14-01-66 [18.8K]3 years ago
3 0
The 5s are 500 and 50
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A large bag of marbles contains red (R) and blue (B) marbles. Marbles are pulled one at a time, recorded, and placed back in the
ehidna [41]
The answer will be A.
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3 years ago
2(15+3m)-7<br><br> Plz explain and answer
Alekssandra [29.7K]
6m+23

You have to use distributive property, so 15x2=30 and 2x3m= 6m. You then subtract 30 from 7 and get 23. 


4 0
3 years ago
Read 2 more answers
I don't understand this question, picture attached.
mina [271]

We can find this using the formula for arc length (where r is the radius of the circle and \theta is the central angle in radians):

\textrm{Arc Length} = r\theta


In our problem, we are given 12 = 8\theta. This means that:

\theta = \dfrac{12}{8} = \boxed{\frac{3}{2}}


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5 0
4 years ago
Solve by substitution. Show each step of your work.<br><br> 2x + y = 7<br><br> 3x + 5y = 14
Monica [59]
Alright...simple...showing all steps.. ;)

You have the equations...

2x+y=7
and
3x+5y=14

To be able to even solve for any of the variables...multiply the equations by...2...and..3...

2x+y=7----*3--> 6x+3y=21
and
3x+5y=14-----*2--->6x+10y=28

Thus,

6x+3y=21
-
6x+10y=28

=========

-7y=-7

y=1

Now, plug y back into any of the original equations....we'll use 2x+y=7 in this case....

2x+(1)=7

2x+1=7
      -1  -1

2x=6

x=3

Thus, the point of intersection for these two equations is (3,1)
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4 years ago
Ppppppppeeeelelelelele help
kirill115 [55]
11/3*6/11=66/33=2
6 24/20-2 15/20=2 9/20
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3 years ago
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