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3 years ago

The answer is: x is choose your answer

Mathematics

1 answer:

katrin2010 [14]3 years ago

3 0

Answer:

All real numbers

Let's find the critical points of the inequality.

−4x+7=17

−4x+7+−7=17+−7(Add -7 to both sides)

−4x=10

−4x−1=10−1

(Divide both sides by -1)

4x=−10

4x=−10(Solve Exponent)

log(4x)=log(−10)(Take log of both sides)

x*(log(4))=log(−10)

x=log(−10)log(4)

x=NaN

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charle [14.2K]

since triangles are similar

4/x = 7x/7

=》 4/x = x

=》x^2 = 4

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3 years ago

Can y'all please help.

sattari [20]

Answer:

See explanation

Step-by-step explanation:

Step 1. Substitute for d to solve for n:

From the first equation:

$d=70-n$

Then substitute it into the second equation:

$0.1(70-n)+0.05n=5.5\\ \\7-0.1n+0.05n=5.5\\ \\7+(-0.05n)=5.5\\ \\-0.05n=5.5-7=-1.5\\ \\n=\dfrac{-1.5}{-0.05}=30$

Step 2: Substitute for n to solve for d:

$d+n=70\\ \\d+30=70\\ \\d=70-30=40$

There are 40 dimes and 30 nikels in the piggy bank

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3 years ago

If the diameter of circle a measures half of the diameter of circle b, then the area of circle b is how many times the area of c

Eduardwww [97]

Circle b:

Diameter = x

Radius = $\frac{x}{2}$

Area = $\pi r^{2} = \pi ( \frac{x}{2} )^{2} = \frac{ \pi x^{2} }{4}$

Circle a:

Diameter = $\frac{x}{2}$

Radius = $\frac{x}{2} * \frac{1}{2} = \frac{x}{4}$

Area = $\pi r^{2} = \pi ( \frac{x}{4} )^{2} = \frac{ \pi x^{2} }{16}$

Thus,

Area of circle b to area of circle a

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= $\frac{ \pi x^{2} }{4}$ × $\frac{ 16 }{\pi x^{2}}$

= 4

Hence, the area of circle b is 4 times the area of circle a.

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