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kkurt [141]
2 years ago
14

Michael read 135 pages in 1 1/2 hours, Select all of the rates that are equivalent to this rate

Mathematics
1 answer:
devlian [24]2 years ago
6 0

The rates that are equivalent to this rate is 90 pages/hr

<h3>Rate of change</h3>

The rate is the number of pages Michael read in 1 hour.

If he read 135 pages in 1 1/2 hours then;

  • 135 pages = 1.5 hours

To determine the rate, we will have:

  • x = 1 hour

Divide both expressions:

135/x = 1.5/1

1.5x = 135

x = 135/1.5

x = 90

Hence the rates that are equivalent to this rate is 90 pages/hr

Learn more on rate here: brainly.com/question/119866

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3a+2x-3y=15<br>Solve for a.<br>Then Solve put the value for a =<br>a+7÷10​
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\huge\bf Question:–

\sf \longmapsto \: 3a+2x−3y=15

\bf \huge \: To  \: Find:–

\boxed{\bf \: Value\: of  \: A}

\huge\bf Solution:–

\sf \longmapsto \: 3a+2x−3y=15

\boxed{ \bf \: Add -2x  \: to  \: both  \: sides}

\sf \longmapsto \: 3a+2x−3y+−2x=15+−2x

\sf \longmapsto \: 3a−3y=−2x+15

\boxed{ \bf \: Add  \: 3y  \: to \:  both  \: sides}

\sf \longmapsto \: 3a−3y+3y=−2x+15+3y

\sf \longmapsto \: 3a=−2x+3y+15

\boxed{\bf \:  \: Divide  \: both  \: sides \:  by \:  3}

\sf \longmapsto \:  \dfrac{3a}{3} =  \dfrac{−2x+3y+15}{3}

\boxed{\bf \:  Cross \: Multiply}

\boxed{\sf \longmapsto \: a =  \dfrac{ - 2}{3} x + y + 5}

______________________________________

\bf \: Put\:The\: Value

\sf \longmapsto \: \dfrac{−2x+3y+15}{3}  +7÷10

\boxed{\bf \: Distribute}

\sf \longmapsto \: \dfrac{ - 2}{3} x+y+5+ \dfrac{7}{10}

\boxed{\bf \: Combine \:  Like \:  terms}

\sf \longmapsto \: \bigg( \dfrac{ - 2}{3} x\bigg) + y +\bigg( 5 +  \dfrac{7}{10} \bigg)

\sf \longmapsto \:  \dfrac{ - 2}{3} x + y +  \dfrac{57}{10}

______________________________________

\boxed{\bf The Answer\: is:–}

\boxed{{\underline{\bf\dfrac{ - 2}{3} x + y +  \dfrac{57}{10}} }}

8 0
2 years ago
Read 2 more answers
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