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aalyn [17]
4 years ago
7

A container at a juicing plant holds 4 2/3 tons of oranges. The plant can juice 1 2/3 tons of oranges per day. At this rate, how

long will it take to empty the container
Mathematics
2 answers:
WITCHER [35]4 years ago
7 0
The answer is 4 days
jolli1 [7]4 years ago
3 0

Answer:

number of days = 2.8 days

Step-by-step explanation:

A container at a juicing plants holds 4 2/3 tons of oranges . The plant can juice 1 2/3 tons of oranges per day . The number of days it will take to empty the container can be calculated as follows:

Firstly, convert the whole number fractions to improper fractions

The container holds 4 2/3 = 14/3 tons of orange

The plant can juice 1 2/3 = 5/3 tons of oranges per day

5/3 tons of oranges =  1 day

14/3 tons of oranges = ? days

cross multiply

number of days = 14/3 ÷ 5/3

number of days = 14/3 × 3/5

number of days = 14/5

number of days = 2.8 days

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Draw a rectangle on a coordinate plane. Choose a scale factor of 2,3,4, or 5, and then dilate the rectangle. How many times grea
TEA [102]
If you have a rectangle that is 2 by 2 and you dilate it by 2, the sides are now 4 x 4. So:
If you dilate it by a factor of 2, the area is 2^2 (4) times as great
A factor of 3 would have an area of 9 times as much.

Conclusion: square the scale factor to get how much greater the area would be.
5 0
4 years ago
Help help help help please i need it :) !!
Maksim231197 [3]

Answer:

Step-by-step explanation:

Area of the field = pi * r^2

r = 230/2 = 115

Area of the field = 3.14 * 115^2 = 41526.5 square feet.

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3 years ago
A certain test preparation course is designed to help students improve their scores on the GMAT exam. A mock exam is given at th
Bogdan [553]

Answer:

95% confidence interval for the average net change is between a lower limit of 11.709 and an upper limit of 30.921.

The critical value that should be used in constructing the confidence interval is 4.303.

Step-by-step explanation:

Confidence interval is given as mean +/- margin of error (E)

mean = (17+20+26)/3 = 63/3 = 21

sd = sqrt[((17-21)^2 + (20-21)^2 + (26-21)^2) ÷ 3] = sqrt(42÷3) = sqrt(14) = 3.74

n = 3

degree of freedom = n-1 = 3-1 = 2

confidence level (C) = 95% = 0.95

significance level = 1 - C = 1 - 0.95 = 0.05 = 5%

critical value (t) corresponding to 2 degrees of freedom and 5% significance level is 4.303.

The critical value is 4.303

E = t×sd/√n = 4.303×3.74/√3 = 9.291

Lower limit of mean = mean - E = 21 - 9.291 = 11.709

Upper limit of mean = mean + E = 21 + 9.291 = 30.291

95% confidence interval is (11.709, 30.391)

8 0
3 years ago
In a study of the progeny of rabbits, Fibonacci (ca. 1170-ca. 1240) encountered the sequence now bearing his name. The sequence
snow_lady [41]

Answer:

The correct answer is 0, 1, 1, 2, 3, 5, 8, 13, 21, 34, 55, 89.

Step-by-step explanation:

In a study of the progeny of rabbits, Fibonacci encountered the sequence now bearing his name.

The sequence is defined recursively as:

a_{n+2} = a_{n} + a_{n+1}, where a1 = 1 and a2 = 1 where n is a natural number.

For n = 0 ; a2 = a0 + a1

⇒ a0 = 0.

For n = 1 ; a3 = a1 + a2 = 1+1

⇒ a3 = 2.

For n = 2 ; a4 = a2 + a3 = 1+2

⇒ a4 = 3.

For n = 3 ; a5 = a3 + a4 = 2+3

⇒ a3 = 5.

For n = 4 ; a6 = a4 + a5 = 3+5

⇒ a6 = 8.

For n = 5 ; a7 = a5 + a6 = 5+8

⇒ a7 = 13.

For n = 6 ; a8 = a6 + a7 = 8+13

⇒ a8 = 21.

For n = 7 ; a9 = a7 + a8 = 21+13

⇒ a9 = 34.

For n = 8 ; a10 = a8 + a9 = 21+34

⇒ a10 = 55.

For n = 9 ; a11 = a9 + a10 = 55+34

⇒ a11 = 89.

Thus the first 12 terms of fibonacci sequence is 0, 1, 1, 2, 3, 5, 8, 13, 21, 34, 55, 89.

6 0
3 years ago
Burning coal yields about 30 x 106 joules of energy per kilogram of coal burned, but only 30% of that energy goed into electrici
abruzzese [7]

Answer:

Number of bulbs which can be lit using 1 kg of coal = 9

Step-by-step explanation:

Energy yielded by burning 1 kg of coal = 30 × 106 joules

                                                                = 3180 joules

Amount of energy that can be used for electricity = 30 % of 3180 joules

                                                                                   = 0.30 × 3180

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Energy needed for lighting one bulb = Wattage of bulb × No. of hours of lighting

⇒ Energy needed for lighting one bulb = 100 × 1

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\text{Now, Number of bulbs which can be lit for one hour = }\frac{954}{100}\\\\\implies\bf\textbf{Number of bulbs = }9.54\approx 9

Hence, Number of bulbs which can be lit using 1 kg of coal = 9

4 0
4 years ago
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