6 sin θ - 3 csc θ = 0
6 sin θ = 3 csc θ = 3/sin θ
6 sin^2 θ = 3
sin^2 θ = 3/6 = 1/2
sin θ = sqrt(1/2)
θ = arcsin(sqrt(1/2)) = 45 degrees.
θ = 45°
You have to do 3 2
--- + ---. You have to do 3 + 2 which is 5, and leave the
8 8 denominators the same, so the answer is 5/8.
Well the answer is 0 because if anything = 0 then it has to be multiplied by 0 so x = 0
Answer:
Step-by-step explanation:
By the Mean Value Theorem, there is at least one number, c, in the interval (1,6) such that
f'(c) = [f(6) - f(1)]/ (6 - 1)
So, f(6) - f(1) = 5f'(c).
Since 2 ≤ f'(c) ≤ 4, 10 ≤ 5f'(c) ≤ 20
So, f(6) - f(1) is between 10 and 20.
A. 168 cm.
V=lwh
4 x 7 x 6 = 168 .
