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3 years ago

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The sum of three consecutive integers is -126. What are the integers?

1 answer:

Zanzabum3 years ago

5 0

Answer:

Three consecutive even integers can be represented by x, x+2, x+4. The sum is 3x+6, which is equal to 108. So its, 3x+6=108.

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A^2 + b^2 + c^2 = 2(a − b − c) − 3. (1) Calculate the value of 2a − 3b + 4c.

Verdich [7]

Answer:

$2a - 3b + 4c = 1$

Step-by-step explanation:

Given

$a^2 + b^2 + c^2 = 2(a - b - c) - 3$

Required

Determine $2a - 3b + 4c$

$a^2 + b^2 + c^2 = 2(a - b - c) - 3$

Open bracket

$a^2 + b^2 + c^2 = 2a - 2b - 2c - 3$

Equate the equation to 0

$a^2 + b^2 + c^2 - 2a + 2b + 2c + 3 = 0$

Express 3 as 1 + 1 + 1

$a^2 + b^2 + c^2 - 2a + 2b + 2c + 1 + 1 + 1 = 0$

Collect like terms

$a^2 - 2a + 1 + b^2 + 2b + 1 + c^2 + 2c + 1 = 0$

Group each terms

$(a^2 - 2a + 1) + (b^2 + 2b + 1) + (c^2 + 2c + 1) = 0$

Factorize (starting with the first bracket)

$(a^2 - a -a + 1) + (b^2 + 2b + 1) + (c^2 + 2c + 1) = 0$

$(a(a - 1) -1(a - 1)) + (b^2 + 2b + 1) + (c^2 + 2c + 1) = 0$

$((a - 1) (a - 1)) + (b^2 + 2b + 1) + (c^2 + 2c + 1) = 0$

$((a - 1)^2) + (b^2 + 2b + 1) + (c^2 + 2c + 1) = 0$

$((a - 1)^2) + (b^2 + b+b + 1) + (c^2 + 2c + 1) = 0$

$((a - 1)^2) + (b(b + 1)+1(b + 1)) + (c^2 + 2c + 1) = 0$

$((a - 1)^2) + ((b + 1)(b + 1)) + (c^2 + 2c + 1) = 0$

$((a - 1)^2) + ((b + 1)^2) + (c^2 + 2c + 1) = 0$

$((a - 1)^2) + ((b + 1)^2) + (c^2 + c+c + 1) = 0$

$((a - 1)^2) + ((b + 1)^2) + (c(c + 1)+1(c + 1)) = 0$

$((a - 1)^2) + ((b + 1)^2) + ((c + 1)(c + 1)) = 0$

$((a - 1)^2) + ((b + 1)^2) + ((c + 1)^2) = 0$

Express 0 as 0 + 0 + 0

$(a - 1)^2 + (b + 1)^2 + (c + 1)^2 = 0 + 0+ 0$

By comparison

$(a - 1)^2 = 0$

$(b + 1)^2 = 0$

$(c + 1)^2 = 0$

Solving for $(a - 1)^2 = 0$

Take square root of both sides

$a - 1 = 0$

Add 1 to both sides

$a - 1 + 1 = 0 + 1$

$a = 1$

Solving for $(b + 1)^2 = 0$

Take square root of both sides

$b + 1 = 0$

Subtract 1 from both sides

$b + 1 - 1 = 0 - 1$

$b = -1$

Solving for $(c + 1)^2 = 0$

Take square root of both sides

$c + 1 = 0$

Subtract 1 from both sides

$c + 1 - 1 = 0 - 1$

$c = -1$

Substitute the values of a, b and c in $2a - 3b + 4c$

$2a - 3b + 4c = 2(1) - 3(-1) + 4(-1)$

$2a - 3b + 4c = 2 +3 -4$

$2a - 3b + 4c = 1$

7 0

4 years ago

Simplify the variable expression by evaluating it's numerical part m-13+42-6

goldfiish [28.3K]

ANSWER

$m + 23$

EXPLANATION

The given expression is

$m - 13 + 42 - 6$

We regroup the numerical parts to get;

$m + 42 - 6 - 13$

Now let us simplify the negative numbers.

$m + 42 - 19$

We now subtract 19 from 42 to get;

$m + 23$

We can't simplify further

Hence the simplest form is:

$m + 23$

3 0

3 years ago

Which of these numbers is irrational?

Sidana [21]

<span>Which of these numbers is irrational?
a. square root of 3
b. 0.25
c. 1/5
d. square root of 9

answer
</span><span>a. square root of 3
</span><span>--------------------------------
What is (-7)^5 in expanded form?
a. -7 • -7 • -7 • -7 • -7
b. -7 • 5
c. (-7) • 7 • (-7) • 7 • (-7) • -7
d. 5 • 5 • 5 • 5 • 5 • 5 • 5

answer

</span><span>a. -7 • -7 • -7 • -7 • -7 </span>

6 0

3 years ago

HELP ASAP!!!! Please!!! Is my answer correct?!?! :) will give brainliest if correct!

MrMuchimi

Vertical stretch of 4 and shift of 4 to the right is: g(x) = 4*f(x-4)

So: g(x) = -12(x-4)

You are correct.

6 0

4 years ago

Sandra has taken 3 Test this Quarter. She has scored an 78%, 76%, and a 93%. Sandra wants to earn at least and 85% for the Quart

algol [13]

Answer:

I think at least a 86% hope this helps, hope i am right

Step-by-step explanation:

5 0

3 years ago

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