(0, 0) → t = 0, w = 0 → w = 0 · 0
(1, 4) → t = 1, w = 4 → w = 1 · 4
(2, 8) → t = 2, w = 8 → w = 2 · 4
(3, 12) → t = 3, w = 12 → w = 3 · 4
<h3>Answer: w = 4t</h3>
An equation which shows a valid step that can be used to solve the given mathematical equation is ![(\sqrt[3]{2x - 6})^3 = (-\sqrt[3]{2x + 6})^3](https://tex.z-dn.net/?f=%28%5Csqrt%5B3%5D%7B2x%20-%206%7D%29%5E3%20%3D%20%28-%5Csqrt%5B3%5D%7B2x%20%2B%206%7D%29%5E3)
<h3>What is an equation?</h3>
An equation simply refers to a mathematical expression that can be used to show the relationship existing between two (2) or more numerical quantities.
In this exercise, you're required to show a valid step which can be used to solve the given mathematical equation. Since both equations are having a cube root, the first step is to take the cube of both sides.
Take the cube of both sides, we have:
![\sqrt[3]{2x - 6} + \sqrt[3]{2x + 6} = 0\\\\(\sqrt[3]{2x - 6})^3 + (\sqrt[3]{2x + 6})^3 = 0^3\\\\(\sqrt[3]{2x - 6})^3 = (-\sqrt[3]{2x + 6})^3](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B2x%20-%206%7D%20%2B%20%5Csqrt%5B3%5D%7B2x%20%2B%206%7D%20%3D%200%5C%5C%5C%5C%28%5Csqrt%5B3%5D%7B2x%20-%206%7D%29%5E3%20%2B%20%28%5Csqrt%5B3%5D%7B2x%20%2B%206%7D%29%5E3%20%3D%200%5E3%5C%5C%5C%5C%28%5Csqrt%5B3%5D%7B2x%20-%206%7D%29%5E3%20%3D%20%28-%5Csqrt%5B3%5D%7B2x%20%2B%206%7D%29%5E3)
Read more on equations here: brainly.com/question/13170908
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Answer: 6√2
Step-by-step explanation:
8 × 9 is 72.
8 can be simplied to 4 × 2.
And 4 can be simplified to 2 × 2.
So far there are three 2s and a 9.
9 can be simplified down to 3 × 3.
Theres a pair of 2s and a pair of 3s, so you multiply 2 × 3 and thats 6 so you put 6 on the outside of the radical. Theres one 2 leftover from all the simplifying so that goes inside the radical to give you 6√2
Answer:
I’m sorry but I can’t answer until you explain