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andreev551 [17]
3 years ago
12

A recipe calls for 2 L of water and 1 L of milk. How many mL is this combined

Mathematics
1 answer:
PilotLPTM [1.2K]3 years ago
6 0
1 liter= 1000 ml 3 liter= 3000 ml
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(PART A PART B) PLEASE HELP!!! DUE TODAY!!!! ❤️
maxonik [38]

Answer:

the anser from what i see should be option 1

Step-by-step explanation:

The reason why i say this is because number 1 is linear which means it is just multipying but your multiplying and adding and its not option 3 because question 5 said the questions started at 1

8 0
3 years ago
Suppose a college student pays $750 for tuition fees. However, she also has to pay $300 for her textbooks (ouch!). What percent
Shalnov [3]

Answer:

Total costs = $700 + $300 = $1000.

 $300 / $1000 = 0.3 = 3%

Step-by-step explanation:

3 0
3 years ago
How do i solve functions?
Maksim231197 [3]
Most quadratic functions(which is what you have there, to a degree of 2) are solved using factoring and the zero product law. If you can not factor then you have to use the quadratic formula or graph it. However this one can be factored.
It's pretty simple to just factor it by inspection but I use the chart method, if you know decomposition that works as well.
Factoring gives us,
(2x + 1)(x - 3) = 0
Then you set each factor to 0 and solve for x,
2x + 1 = 0
2x =  - 1
x =  \frac{ - 1}{2}
And the second one,
x - 3 = 0
x = 3
The solutions to this equation are
x = -1/2, 3
6 0
3 years ago
Given that cos 160= -q, express each of the following in terms of q:
GenaCL600 [577]
Hello,

cos 160°=-q

cos 20°=-cos 160°=q

sin 20°=√(1-q²)=sin 160°

tan -20°=tan 160=√(1-q²)/-q

cos 70°=sin 20°=√(1-q²)
6 0
4 years ago
Read 2 more answers
Two boats depart from a port located at (–8, 1) in a coordinate system measured in kilometers and travel in a positive x-directi
miss Akunina [59]

Answer:

\left\{\begin{array}{l}y=-\dfrac{1}{9}x^2 +\dfrac{2}{9}x+\dfrac{89}{9}\\ \\y=\dfrac{1}{8}x^2 -7\end{array}\right.

Step-by-step explanation:

1st boat:

Parabola equation:

y=ax^2 +bx+c

The x-coordinate of the vertex:

x_v=-\dfrac{b}{2a}\Rightarrow -\dfrac{b}{2a}=1\\ \\b=-2a

Equation:

y=ax^2 -2ax+c

The y-coordinate of the vertex:

y_v=a\cdot 1^2-2a\cdot 1+c\Rightarrow a-2a+c=10\\ \\c-a=10

Parabola passes through the point (-8,1), so

1=a\cdot (-8)^2-2a\cdot (-8)+c\\ \\80a+c=1

Solve:

c=10+a\\ \\80a+10+a=1\\ \\81a=-9\\ \\a=-\dfrac{1}{9}\\ \\b=-2a=\dfrac{2}{9}\\ \\c=10-\dfrac{1}{9}=\dfrac{89}{9}

Parabola equation:

y=-\dfrac{1}{9}x^2 +\dfrac{2}{9}x+\dfrac{89}{9}

2nd boat:

Parabola equation:

y=ax^2 +bx+c

The x-coordinate of the vertex:

x_v=-\dfrac{b}{2a}\Rightarrow -\dfrac{b}{2a}=0\\ \\b=0

Equation:

y=ax^2+c

The y-coordinate of the vertex:

y_v=a\cdot 0^2+c\Rightarrow c=-7

Parabola passes through the point (-8,1), so

1=a\cdot (-8)^2-7\\ \\64a-7=1

Solve:

a=-\dfrac{1}{8}\\ \\b=0\\ \\c=-7

Parabola equation:

y=\dfrac{1}{8}x^2 -7

System of two equations:

\left\{\begin{array}{l}y=-\dfrac{1}{9}x^2 +\dfrac{2}{9}x+\dfrac{89}{9}\\ \\y=\dfrac{1}{8}x^2 -7\end{array}\right.

7 0
3 years ago
Read 2 more answers
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