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Nikitich [7]
3 years ago
12

Which of the following triangles are impossible? Check all that apply. a triangle with angles of 28º, 72º, and 80º a triangle wi

th angles of 17º, 57º, and 106º a triangle with angles of 13º, 48º, and 131º
Mathematics
1 answer:
katrin2010 [14]3 years ago
7 0

Answer:

a triangle with angles of 13, 48, and 131 degrees

Step-by-step explanation:

All the triangles equal to 180

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What is 347,168 round to then thoudands
Finger [1]

Answer:

347,168 rounded to the nearest ten thousands would be 350,000.

Step-by-step explanation:

When rounding to the nearest ten thousands, you rely on the thousands place value to indicate whether to round up or down. 5 or higher give it a shove, 4 or less let it rest. 7 is in the thousands place meaning we round up. 4 is in the ten thousands place meaning it becomes 5. 347,168 rounded to the nearest ten thousands would be 350,000.

8 0
3 years ago
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Suppose it is known that 60% of radio listeners at a particular college are smokers. A sample of 500 students from the college i
vladimir1956 [14]

Answer:

The probability that at least 280 of these students are smokers is 0.9664.

Step-by-step explanation:

Let the random variable <em>X</em> be defined as the number of students at a particular college who are smokers

The random variable <em>X</em> follows a Binomial distribution with parameters n = 500 and p = 0.60.

But the sample selected is too large and the probability of success is close to 0.50.

So a Normal approximation to binomial can be applied to approximate the distribution of X if the following conditions are satisfied:

1. np ≥ 10

2. n(1 - p) ≥ 10

Check the conditions as follows:

 np=500\times 0.60=300>10\\n(1-p)=500\times(1-0.60)=200>10

Thus, a Normal approximation to binomial can be applied.

So,  

X\sim N(\mu=600, \sigma=\sqrt{120})

Compute the probability that at least 280 of these students are smokers as follows:

Apply continuity correction:

P (X ≥ 280) = P (X > 280 + 0.50)

                   = P (X > 280.50)

                   =P(\frac{X-\mu}{\sigma}>\frac{280-300}{\sqrt{120}}\\=P(Z>-1.83)\\=P(Z

*Use a <em>z</em>-table for the probability.

Thus, the probability that at least 280 of these students are smokers is 0.9664.

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2 years ago
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