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choli [55]
3 years ago
6

the coordinates of one point of a line segment are (-2,-7). The line segment is 12 units long. Give three possible coordinates o

f the line segment’s other end point.
Mathematics
1 answer:
valentinak56 [21]3 years ago
4 0

(-2,-19) , (-2, 5), ( 2,10)

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A 15 kg bag of strawberry for $8 _____ per bag
jok3333 [9.3K]
This makes no sense tbh.
6 0
3 years ago
Jeannie is an experienced business traveler, often traveling back and forth from San Francisco to the East Coast several times p
lesya692 [45]

Answer:

The probability that Jeannie will miss her flight because her total time for catching her plane exceeds one hour is 0.0026.

Jeannie should leave her office 55 minutes early.

Step-by-step explanation:

Let <em>X</em> = time it requires Jeannie to catch her plane.

The random variable <em>X</em> is normally distributed, N(46, 5).

Compute the probability that Jeannie will miss her flight because her total time for catching her plane exceeds one hour as follows:

P(X>60)=P(\frac{X-\mu}{\sigma} >\frac{60-46}{5} )\\=P(Z>2.8)\\=1-P(Z

The probability that Jeannie will miss her flight because her total time for catching her plane exceeds one hour is 0.0026.

Now, it is provided that Jeannie has 96% chance of catching her flight if she reaches under <em>x</em> minutes.

That is, P (X < x) = 0.96.

Compute the value of <em>x</em> as follows:

P(X

**Use the <em>z</em>-table to compute the value of <em>z</em>.

The value of <em>z</em> is 1.751.

Compute the value of <em>x</em> as follows:

z=\frac{x-46}{5}\\ 1.751=\frac{x-46}{5}\\x=46+(1.751\times5)\\=54.755\\\approx 55

Thus, Jeannie should leave her office 55 minutes early.

4 0
3 years ago
1:The bee hummingbird is the smallest species. It
olasank [31]
1.7x 10 =17


Hope this helps
3 0
3 years ago
SOLVE THOSE TWO PROBLEMS PLEASEEE I REALLY NEED HELP
BabaBlast [244]

Answer:

I and G

Step-by-step explanation:

3 0
3 years ago
the diameter of a piston for an automobile is 3 11/16in with tolerence of 1/64in. find the upper and lower limits of the pistons
padilas [110]

Upper Tolerance

Remark

The 11/16 is the only thing that will be affected. The three won't go up or down when we add 1/64 so we should just work with the 11/16. We need only add 11/16 and 1/64 together to see what the upper range is. Later on we can add 3 into the mix.

Solution

<u>Upper Limit</u>

\dfrac{11}{16} +  \dfrac{1}{64}

Now change the 11/16 into 64. Multiply numerator and denominator or 11/16 by 4

\dfrac{11*4}{16*4} +  \dfrac{1}{64}

\dfrac{11*4}{16*4} +  \dfrac{1}{64} Which results in

\dfrac{44}{64} +  \dfrac{1}{64}

With a final result for the fractions of 45/64

So the upper tolerance = 3 45/64

<u>Lower Tolerance</u>

Just follow the same steps as you did for the upper tolerance except you subtract 1/64 like this.

\dfrac{11}{16} - \dfrac{1}{64}

Your answer should be 3 and 43/64


4 0
3 years ago
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