Answer:
E. x^2 = 39 + 10x
Step-by-step explanation:
It helps to do one piece of the sentence at a time.
"A number, x, squared is 39 more than the product of 10 and x"
x
"A number, x, squared is 39 more than the product of 10 and x"
x^2 =
"A number, x, squared is 39 more than the product of 10 and x"
x^2 = 39 +
"A number, x, squared is 39 more than the product of 10 and x"
x^2 = 39 + 10x
Answer: E. x^2 = 39 + 10x
Answer:
The answer is -19
Step-by-step explanation:
Given information -19y^2 , y=-1
-19 * y^2
-19 * (-1)^2
-19 * 1 = -19
When you represent intervals on the number line, you're including full dots, excluding empty dots, and you're considering numbers highlighted by the line.
In the first case, you've highlighted everything before -2 (full dot, thus included), and everything after 1 (empty dot, excluded). So, the set would be

or, in interval notation,
![(-\infty,-2]\cup (1,\infty)](https://tex.z-dn.net/?f=%28-%5Cinfty%2C-2%5D%5Ccup%20%281%2C%5Cinfty%29)
In the second case, you are looking for all numbers between -3 and 5. This interval is symmetric with respect to 1: you're considering all numbers that are at most 4 units away from 1, both to the left and to the right.
This means that the difference between your numbers at 1 must be at most 4, which is modelled by

where the absolute values guarantees that you'll pick numbers to the left and to the right of 1.
Answer:
see explanation
Step-by-step explanation:
To calculate the first 3 terms substitute n = 1, 2, 3 into the n th term rule
= (3 × 1) + 2 = 3 + 2 = 5
= (3 × 2) + 2 = 6 + 2 = 8
= (3 × 3) + 2 = 9 + 2 = 11
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substitute n = 10 into the n th term rule
= (3 × 10) + 2 = 30 + 2 = 32
Answer:
D. 99
Step-by-step explanation:
Well they were losing money so 11 times 9 = 99