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hichkok12 [17]
3 years ago
6

To have batting averages over 0.500,how many hits in 45 times at bat would Raul and Karen need

Mathematics
2 answers:
Morgarella [4.7K]3 years ago
6 0
You would have to multiply 0.500(0.5) to 45 and you would get 22.5
shtirl [24]3 years ago
6 0

Answer:

They would need 23 hits at 45 times at bat.

Step-by-step explanation:

Let x be the number of hits.

We can set up the following inequality:  \frac{x}{45} >0.500

Now, multiplying both sides by 45 we get the solution:  

x > 22.5

To have individual batting averages over 0.500, Raul and Karen would each need 23 hits for every 45 times at bat.

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What is the least common multiple between 8 10 and 12
DochEvi [55]
The LCM is the lowest number that is a multiple of all three numbers. 
First, list the multiples of each number
8: 8, 16, 24, 32,40 48, 56, 64, 72, 80, 88, 96, 104, 112, 120
10: 10, 20, 30 40, 50, 60, 70, 80, 90, 100, 110, 120
12: 12, 24, 36, 48, 60, 72, 84, 96, 108, 120

The LCM is 120 because there is no lower number that is a multiple of all three numbers.
Hope this helped!
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3 years ago
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choli [55]
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8 0
3 years ago
Given the equation:
Alisiya [41]

Answer:

x = 1 and x = \frac{-4}{5}

Step-by-step explanation:

In this equation, a=5, b=-1, c=-4.

Plug these into the quadratic formula:

x = \frac{1+\sqrt{-1^{2}-(-4)(5)(-4) } }{2(5)}   and x = \frac{1-\sqrt{-1^{2}-(-4)(5)(-4) } }{2(5)}

Now, simplify the equations:

x = \frac{1+\sqrt{81} }{10} = \frac{1+9}{10} = \frac{10}{10} = 1

and

x = \frac{1-\sqrt{81} }{10} = \frac{1-9}{10} = \frac{-8}{10} = \frac{-4}{5}

5 0
3 years ago
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The Answer is D. 1/3
7 0
3 years ago
Read 2 more answers
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nexus9112 [7]

Answer:

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3 years ago
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