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2 years ago

The following formula relates three quantities force mass and acccelerations F=ma

Mathematics

1 answer:

belka [17]2 years ago

6 0

True. Dissect "F=ma" and you'll get "Force," "mass" and "acceleration."

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Mr. Jenkins was arranging chairs for a school awards assembly. Each row contained 15 chairs. If there were 21 rows. how many cha

g100num [7]

Answer:

315 chairs

Step-by-step explanation:

This question can instill your quick calculation skills which can be very useful when it comes to event planning.

1 row of chairs = 15 chairs

21 rows of chairs = 15 x 21

= 315 chairs.

5 0

2 years ago

Calculate s26 for the arithmetic sequence in which a14=4.1 and the common difference is d=1.7

sweet-ann [11.9K]

Answer:

The value of $s_{26}=84.5$

Step-by-step explanation:

We have given $a_{14}=4.1$

d=1.7

We have to find $s_{26}$

So, $a_{14}=a+13d$ from the formula

$a_n=a+(n-1)d$

When n=14

$a_{14}=a+(14-1)(1.7)=a+13(1.7)$

$4.1=a+22.1$

$-18=a$

$a=-18$

Using the formula:

$s_n=\frac{n}{2}[2a+(n-1)d$

When n=26

$s_{26}=\frac{26}{2}[2(-18)+(26-1)(1.7)]$

On simplification we get:

$s_{26}=84.5$

8 0

2 years ago

Please help me please

Norma-Jean [14]

Im blind SKDJFJNEDKODNANSRNFIS

3 0

2 years ago

Read 2 more answers

In the kite , AK=9 , JK=15 , and AM=16 .

Veronika [31]

Answer:

The Length of JM is 20.

Step-by-step explanation:

Given,

JKLM is a kite in which JL and KM are the diagonals that intersect at point A.

Length of AK = 9

Length of JK = 15

Length of AM = 16

Solution,

Since JKLM is a kite. And JL and KM are the diagonals.

And we know that the diagonals of a kite perpendicularly bisects each other.

So, JL ⊥ KM.

Therefore ΔJAK is aright angled triangle.

Now according to Pythagoras Theorem which states that;

"The square of the hypotenuse is equal to the sum of the square of base and square of perpendicular".

$JK^2=KA^2+AJ^2$

On putting the values, we get;

$(15)^2=9^2+AJ^2\\\\225=81+AJ^2\\\\AJ^2=225-81=144$

On taking square root onboth side, we get;

$\sqrt{AJ^2} =\sqrt{144}\\\\AJ=12$

Again By Pythagoras Theorem,

$AJ^2+AM^2=JM^2$

On putting the values, we get;

$JM^2=(12)^2+(16)^2\\\\JM^2=144+256=400$

On taking square root onboth side, we get;

$\sqrt {JM^2}=\sqrt{400}\\\\JM=20$

Hence The Length of JM is 20.

4 0

3 years ago

Pl help it’s for a grade

True [87]

I think the answer is b
I hope this helps :)

5 0

3 years ago

Read 2 more answers