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horsena [70]
2 years ago
6

The following formula relates three quantities force mass and acccelerations F=ma

Mathematics
1 answer:
belka [17]2 years ago
6 0
True.  Dissect "F=ma" and you'll get "Force," "mass" and "acceleration."
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Mr. Jenkins was arranging chairs for a school awards assembly. Each row contained 15 chairs. If there were 21 rows. how many cha
g100num [7]

Answer:

315 chairs

Step-by-step explanation:

This question can instill your quick calculation skills which can be very useful when it comes to event planning.

1 row of chairs = 15 chairs

21 rows of chairs = 15 x 21

= 315 chairs.

5 0
2 years ago
Calculate s26 for the arithmetic sequence in which a14=4.1 and the common difference is d=1.7
sweet-ann [11.9K]

Answer:

The value of s_{26}=84.5

Step-by-step explanation:

We have given  a_{14}=4.1

d=1.7

We have to find s_{26}

So, a_{14}=a+13d from the formula

a_n=a+(n-1)d

When n=14

a_{14}=a+(14-1)(1.7)=a+13(1.7)

4.1=a+22.1

-18=a

a=-18

Using the formula:

s_n=\frac{n}{2}[2a+(n-1)d

When n=26

s_{26}=\frac{26}{2}[2(-18)+(26-1)(1.7)]

On simplification we get:

s_{26}=84.5



8 0
2 years ago
Please help me please
Norma-Jean [14]
Im blind SKDJFJNEDKODNANSRNFIS
3 0
2 years ago
Read 2 more answers
In the kite , AK=9 , JK=15 , and AM=16 .
Veronika [31]

Answer:

The Length of JM is 20.

Step-by-step explanation:

Given,

JKLM is a kite in which JL and KM are the diagonals that intersect at point A.

Length of AK = 9    

Length of JK = 15  

Length of AM = 16

Solution,

Since JKLM is a kite. And JL and KM are the diagonals.

And we know that the diagonals of a kite perpendicularly bisects each other.

So, JL ⊥ KM.

Therefore ΔJAK is aright angled triangle.

Now according to Pythagoras Theorem which states that;

"The square of the hypotenuse is equal to the sum of the square of base and square of perpendicular".

JK^2=KA^2+AJ^2

On putting the values, we get;

(15)^2=9^2+AJ^2\\\\225=81+AJ^2\\\\AJ^2=225-81=144

On taking square root onboth side, we get;

\sqrt{AJ^2} =\sqrt{144}\\\\AJ=12

Again By Pythagoras Theorem,

AJ^2+AM^2=JM^2

On putting the values, we get;

JM^2=(12)^2+(16)^2\\\\JM^2=144+256=400

On taking square root onboth side, we get;

\sqrt {JM^2}=\sqrt{400}\\\\JM=20

Hence The Length of JM is 20.

4 0
3 years ago
Pl help it’s for a grade
True [87]
I think the answer is b
I hope this helps :)
5 0
3 years ago
Read 2 more answers
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