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3 years ago

It took a ball 1 minute to roll 90 feet. what was ths balls average rate of speed in feet per second

Mathematics

1 answer:

topjm [15]3 years ago

8 0

1.5 ft per second.

Divide the 90 by 60.

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Jim has three times as many comic books as Charles Charles has two thirds as many books as Bob Bob has 27 books how many comic b

agasfer [191]

Bob has 27 books.
Charles has two thirds as many books as Bob.

$27 \times \frac{2}{3}=9 \times 2=18$

Charles has 18 books.
Jim has three times as many books as Charles.

$18 \times 3=54$

Jim has 54 comic books.

6 0

3 years ago

Find the unit price for<br> $3.78 for a 6-pack

bixtya [17]

Answer:

3.72 answer is your answer

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3 years ago

Find the value of x, y, and z in the image below.

Yakvenalex [24]

Answer:

Step-by-step explanation:

y=18°

x=64°

x+y+z=180

64+18+z=180

82+z=180

z=180-82=98°

7 0

3 years ago

Read 2 more answers

Jenna often babysits to earn extra money. On Friday nights , she made $42 for for babysitting 3 hours.

aivan3 [116]

She made 14 dollars and hour if that was your question

8 0

3 years ago

I'm giving brainliest to the most helpful answer. For 50 points:

Alenkinab [10]

Answer:

1) $\displaystyle\frac{5}{18}\approx27.78\%$

2) $\displaystyle\frac{4}{7}\approx57.14\%$

3) $\displaystyle \frac{13}{16}=81.25\%$

Step-by-step explanation:

We are given a two-way frequency table. Using the table, we will determine the probability for each case.

Question 1)

P(A Student With A Part Time Job Without A Car)

Using the first column, the total number of students that have a part time job is 78+30=108.

Likewise, using the first column, we can see that out of those 108 students, 30 do not have a car.

Hence, the probability that a student with a part time job without a car is:

$\displaystyle P=\frac{30}{108}=\frac{5}{18}\approx27.78\%$

Question 2)

P(No Car | Does Not Have A Part Time Job)

Remember that the vertical line means conditional probability.

So, we want the probability of a student having no car given that they do not have a part time job.

Using the second column, we can see that the total number of students that do not have a part time job is 18+24=42.

Likewise, using the second column, 24 do not have a car.

Hence, the probability that a student with a part time job without a car is:

$\displaystyle P=\frac{24}{42}=\frac{4}{7}\approx57.14\%$

Question 3)

P(Part Time Job | Car)

So, we want to probability of a student having a part time job given that they have a car.

Using the first row, the total students that have a car is 78+18=96.

And of those 96 students, 78 have a part time job.

Hence, the probability that a student with a car has a part time job is given by:

$\displaystyle P=\frac{78}{96}=\frac{13}{16}=81.25\%$

4 0

3 years ago