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Serggg [28]
3 years ago
7

PLLLZZZZ HELPPP MEE

Mathematics
1 answer:
Amanda [17]3 years ago
3 0

Answer:

  1. construct PQ
  2. construct circles of radius PQ centered at P and Q
  3. label one of the points of intersection R
  4. Construct PR and QR

Step-by-step explanation:

You should actually do this some time. It will help you understand the construction process and help you remember the steps. It may even help you figure out why it works.

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PLEASE HELPPPPPPP
uysha [10]

Answer:

the answer would be 1,-8

6 0
2 years ago
One of the roots of the quadratic equation dx^2+cx+p=0 is twice the other, find the relationship between d, c and p
scZoUnD [109]

Answer:

c^2 = 9dp

Step-by-step explanation:

Given

dx^2 + cx + p = 0

Let the roots be \alpha and \beta

So:

\alpha = 2\beta

Required

Determine the relationship between d, c and p

dx^2 + cx + p = 0

Divide through by d

\frac{dx^2}{d} + \frac{cx}{d} + \frac{p}{d} = 0

x^2 + \frac{c}{d}x + \frac{p}{d} = 0

A quadratic equation has the form:

x^2 - (\alpha + \beta)x + \alpha \beta = 0

So:

x^2 - (2\beta+ \beta)x + \beta*\beta = 0

x^2 - (3\beta)x + \beta^2 = 0

So, we have:

\frac{c}{d} = -3\beta -- (1)

and

\frac{p}{d} = \beta^2 -- (2)

Make \beta the subject in (1)

\frac{c}{d} = -3\beta

\beta = -\frac{c}{3d}

Substitute \beta = -\frac{c}{3d} in (2)

\frac{p}{d} = (-\frac{c}{3d})^2

\frac{p}{d} = \frac{c^2}{9d^2}

Multiply both sides by d

d * \frac{p}{d} = \frac{c^2}{9d^2}*d

p = \frac{c^2}{9d}

Cross Multiply

9dp = c^2

or

c^2 = 9dp

Hence, the relationship between d, c and p is: c^2 = 9dp

8 0
3 years ago
WILL GIVE BRAINLIEST!
Brrunno [24]

Answer:

The graph is not a function of x because x=0 intersects the graph at two points.

Step-by-step explanation:

The vertical line test is when you draw, well, a vertical line through the graph. the slope of a vertical line is undefined, and the formula written as x=_. So we can eliminate the choices with y=_.

We can clearly see that this graph isn't a function, so we can eliminate the answer choices that say that the graph is a function.

Just in case, draw a line at x=0, to check that it does indeed cross the graph in 2 places.

5 0
3 years ago
If the flare is launched with an initial velocity of 144 feet per second, find the height after 2 seconds. The answer is not 288
Rashid [163]
H= ut -16 t^2

h = 144(2) - 16 (4)

= 288 - 64 = 224
4 0
2 years ago
Help 15 points ! -8m -3m
Brut [27]

Answer:

-11m

Step-by-step explanation:

subtract the expression

8 0
2 years ago
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