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3 years ago

13

Diviving mixed numbers 2 1/2 divide by 1 1/7

2 answers:

jarptica [38.1K]3 years ago

6 0

$2\frac{1}{2}=\frac{2\times2+1}{2}=\frac{5}{2}\\\\1\frac{1}{7}=\frac{1\times7+1}{7}=\frac{8}{7}\\\\2\frac{1}{2}:1\frac{1}{7}=\frac{5}{2}:\frac{8}{7}=\frac{5}{2}\times\frac{7}{8}=\frac{35}{16}=\frac{32+3}{16}=\frac{32}{16}+\frac{3}{16}=\boxed{2\frac{3}{16}}$

Olenka [21]3 years ago

4 0

I'm going to change those to 5/2 and 8/7
Dividing is the same multiplying by the reciprocal (reciprocal of x is 1/x, reciprocal of x/y is y/x)
So (5/2)/(8/7)=(5/2)*(7/8)=(5*7)/(2*8)=35/16
Final answer: 35/16

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55% as a fraction in simplest form.

nirvana33 [79]

Answer: 11/20
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3 years ago

Rachel is a stunt driver. One time, during a gig where she escaped from a building about to explode(!), she drove to get to the

lara31 [8.8K]

Answer:

$D(t)=-24t+166$

Step-by-step explanation:

Let

D(t) = the distance to the safe zone (measured in meters)

t = time (measured in seconds)

<u>Given:</u>

Rachel's rate = 24 meters per second

At $t_1=4$ seconds $D(t_1)=70$ meters

<u>Find:</u> D(t)

Rachel's rate is the slope of the function D(t). Since the distance is decreasing when the time is increasing, the slope must be negative.

Hence, the function expression is

$D(t)=-24t+b$

To find b, substitute $t_1=4$ and $D(t_1)=70:$

$70=-24\cdot 4+b\\ \\70=-96+b\\ \\b=70+96\\ \\b=166$

So,

$D(t)=-24t+166$

7 0

3 years ago

Una gruesa de lapices(144 unidades) cuesta $6.800. Cuanto cuestan 450 lapices

irina [24]

Write and solve an equation of ratios:

$6,800 x
------------- = --------------
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3 years ago

What is the slope of the line on the graph below?

agasfer [191]

Answer:

Your answer will be one-third. I hope this will help you.

Step-by-step explanation:

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3 years ago

Read 2 more answers

Please help i dont understand what its asking

Arisa [49]

Multiply both the numerator and denominator by $2+\sqrt3$ , which is called the "conjugate" of $2-\sqrt3$ :

$\dfrac{5+\sqrt3}{2-\sqrt3}\cdot\dfrac{2+\sqrt3}{2+\sqrt3}$

Why do we pick this number? Recall the difference of squares factorization:

$a^2-b^2=(a-b)(a+b)$

Now replace $a=2$ and $b=\sqrt3$ . Then

$(2-\sqrt3)(2+\sqrt3)=2^2-(\sqrt3)^2=4-3=1$

So in your fraction, you end up with

$\dfrac{5+\sqrt3}{2-\sqrt3}=\dfrac{(5+\sqrt3)(2+\sqrt3)}1=(5+\sqrt3)(2+\sqrt3)$

Finally, just expand the product.

$(5+\sqrt3)(2+\sqrt3)=10+7\sqrt3+(\sqrt3)^2=\boxed{13+7\sqrt3}$

7 0

3 years ago