Question

(05.05)On a coordinate plane, the coordinates of vertices R and T for a polygon are R(−6, 2) and T(1, 2). What is the length of Side RT of the polygon?

Answer 1

Answer:

The length of Side RT of the polygon is $7\ units$

Step-by-step explanation:

we know that

the formula to calculate the distance between two points is equal to

$d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}$

we have

$R(-6,2)\\T(1,2)$  

substitute the values

$d=\sqrt{(2-2)^{2}+(1+6)^{2}}$

$d=\sqrt{(0)^{2}+(7)^{2}}$

$dRT=7\ units$

Answer 2

Answer:  The length of side RT is 7 units.

Step-by-step explanation:  Given that the co-ordinates of vertices R and T for a polygon on a co-ordinates plane are R(−6, 2) and T(1, 2).

We are to find the length RT of the polygon.

We know that

the length of a line segment with endpoints P(a, b) and Q(c, d) is equal to the distance between the points P and Q.

By distance formula, the distance between P(a, b) and Q(c, d) is

$D=\sqrt{(c-a)^2+(d-b)^2}.$

So, the distance between R(−6, 2) and T(1, 2) is given by

$RT=\sqrt{(1+6)^2+(2-2)^2}=\sqrt{49+0}=7.$

Thus, the length of side RT is 7 units.