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2 years ago

How to solve linear equation

Mathematics

2 answers:

ch4aika [34]2 years ago

6 0

Answer:

1.Step 1: Simplify each side, if needed.

2.Step 2: Use Add./Sub. Properties to move the variable term to one side and all other terms to the other side.

3.Step 3: Use Mult./Div. ...

4.Step 4: Check your answer.

I find this is the quickest and easiest way to approach linear equations.

5.Example 6: Solve for the variable.

Nata [24]2 years ago

4 0

You can use elimination and substitution method

EXAMPLE :

Given :

2x + y = 5

3x - 5y = 1

2x + y = 5 (× -5)

3x - 5y = 1

__________

-10x - 5y = - 25

3x - 5y = 1

____________ _ (elimination)

-13x = - 26

x = - 26/-13

x = 2

Substitution x = 2 to 2x + y = 5 :

2x + y = 5

2(2) + y = 5

4 + y = 5

y = 5 - 4

y = 1

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2 years ago

The length of a rectangle is increasing at a rate of 6 cm/s and its width is increasing at a rate of 5 cm/s. When

atroni [7]

Answer:

The area of the rectangle is increasing at a rate of 84 square centimeters per second.

Step-by-step explanation:

The area for a rectangle is given by the formula:

$A=w\ell$

Where w is the width and l is the length.

We are given that the length of the rectangle is increasing at a rate of 6 cm/s and that the width is increasing at a rate of 5 cm/s. In other words, dl/dt = 6 and dw/dt = 5.

First, differentiate the equation with respect to t, where w and l are both functions of t:

$\displaystyle \frac{dA}{dt}=\frac{d}{dt}\left[w\ell]$

By the Product Rule:

$\displaystyle \frac{dA}{dt}=\frac{dw}{dt}\ell +\frac{d\ell}{dt}w$

Since we know that dl/dt = 6 and that dw/dt = 5:

$\displaystyle \frac{dA}{dt}=5\ell + 6w$

We want to find the rate at which the area is increasing when the length is 12 cm and the width is 4 cm. Substitute:

$\displaystyle \frac{dA}{dt}=5(12)+6(4)=84\text{ cm}^2\text{/s}$

The area of the rectangle is increasing at a rate of 84 square centimeters per second.

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3 years ago

22% of the customers visiting the suit department of a certain store will purchase a suit, 30% will purchase a shirt and 28% wil

Ulleksa [173]

Answer:

If there are 1000 customers in the store one week, how many will purchase exactly one of these items

1000 CUSTOMERS*28%=280

Step-by-step explanation:

A The event that a persons buys a suit

B The event that a person buys a shirt

C The event that a person buys a tie

P(A)= 22%

P(B)= 30%

P(C)= 28%

P(AB)= 11%

P(AC)= 14%

P(BC)= 10%

P(ABC)= 6%

A u B u C Is the event that any item is bougth

AC u AC u BC Is the event that any two events occured

So the wanted probability is

P[(A u B u C )(AB u AC u BC)^c

P[(A u B u C )=P(AB)+ P(BC)+P(BC)

P[(A u B u C ) =0.22+0.30+0.28-0.11-0.14.-0.10+0.06

=0,51

0,51=+0,23+P[(A u B u C )(AB u AC u BC)^c

=0,28

1000 CUSTOMERS*28%=280

6 0

3 years ago