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2 years ago

How to solve linear equation

Mathematics

2 answers:

ch4aika [34]2 years ago

6 0

Answer:

1.Step 1: Simplify each side, if needed.

2.Step 2: Use Add./Sub. Properties to move the variable term to one side and all other terms to the other side.

3.Step 3: Use Mult./Div. ...

4.Step 4: Check your answer.

I find this is the quickest and easiest way to approach linear equations.

5.Example 6: Solve for the variable.

Nata [24]2 years ago

4 0

You can use elimination and substitution method

EXAMPLE :

Given :

2x + y = 5

3x - 5y = 1

2x + y = 5 (× -5)

3x - 5y = 1

__________

-10x - 5y = - 25

3x - 5y = 1

____________ _ (elimination)

-13x = - 26

x = - 26/-13

x = 2

Substitution x = 2 to 2x + y = 5 :

2x + y = 5

2(2) + y = 5

4 + y = 5

y = 5 - 4

y = 1

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Step-by-step explanation:

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2 years ago

1) construct 3 equations starting with x= -2

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2 years ago

Factor 16x^2 + 49. Check your work.

Shtirlitz [24]

Answer:

$16x^2+49=(x-\frac{7i}{4})(x+\frac{7i}{4})$

Step-by-step explanation:

Given : Expression $16x^2+49$

To find : Factor the expression ?

Solution :

The given expression is a quadratic function $y=ax^2+bx+c$ the solution is $x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}$

On comparing with general form,

a=16, b=0, c=49

Substitute in the formula,

$x=\frac{-0\pm\sqrt{0^2-4(16)(49)}}{2(16)}$

$x=\frac{\pm\sqrt{-3136}}{32}$

$x=\frac{\pm56i}{32}$

$x=\frac{56i}{32},\frac{-56i}{32}$

$x=\frac{7i}{4},\frac{-7i}{4}$

Factors are $(x-\frac{7i}{4}),(x+\frac{7i}{4})$

Therefore, $16x^2+49=(x-\frac{7i}{4})(x+\frac{7i}{4})$

4 0

3 years ago

The maximum value of 12 sin 0-9 sin²0 is: -

jeka57 [31]

Answer:

Step-by-step explanation:

The question is not clear. You have indicated the original function as 12sin(0) - 9sin²(0)

If so, the solution is trivial. At 0, sin(0) is 0 so the solution is 0

However, I will assume you meant the angle to be $\theta$ rather than 0 which makes sense and proceed accordingly

We can find the maximum or minimum of any function by finding the first derivate and setting it equal to 0

The original function is

$f(\theta) = 12sin(\theta) - 9 sin^2(\theta)$

Taking the first derivative of this with respect to $\theta$ and setting it equal to 0 lets us solve for the maximum (or minimum) value

The first derivative of $f(\theta)$ w.r.t $\theta$ is

$12\cos\left(\theta\right)-18\cos\left(\theta\right)\sin\left(\theta\right)$

And setting this = 0 gives

$12\cos\left(\theta\right)-18\cos\left(\theta\right)\sin\left(\theta\right) = 0$

Eliminating $cos(\theta)$ on both sides and solving for $sin(\theta)$ gives us

$sin(\theta) = \frac{12}{18} = \frac{2}{3}$

Plugging this value of $sin(\theta)$ into the original equation gives us

$12(\frac{2}{3}) - 9(\frac{4}{9} ) = 8 - 4 = 4$

This is the maximum value that the function can acquire. The attached graph shows this as correct

3 0

1 year ago

Plz i need help i promise i will mark brainliest

bulgar [2K]

Answer:

Step-by-step explanation:

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2 years ago