If a rectangle has a length of 16 centimeters and a width of 20 centimeters, what is the area?

Mathematics

1 answer:

KATRIN_1 [288]3 years ago

4 0

Answer:The answer is 320

Step-by-step explanation:

16x20=320

You might be interested in

You have a map of an area in France. The scale used is 2cm:8km. You want to ride to a national park. The park is shown on the ma

slega [8]

Divide the distance on the map by 2 to get the number of 8km segments there are, then multiply that by 8km for total distance.

16 cm / 2cm = 8

8 x 8km = 64km total.

8 0

4 years ago

How do I know if a positive integer is even based on its prime factorization?

faust18 [17]

To know if it's even based on it's prime factorization, check to see if it is a multiple of 2. If it is, it is an even number. If it is not, it is an odd number.

5 0

4 years ago

2x² - 5x+1 has roots alpha and beta. Find alpha⁴+beta⁴ without solving the equation.

shepuryov [24]

Answer:

Step-by-step explanation:

$\alpha+\beta=\dfrac{5}{2} \\\\\alpha*\beta=\dfrac{1}{2} \\\\\alpha^2+\beta^2=\dfrac{21}{4} \ (see\ previous\ post)\\\\(\alpha+\beta)^4=\dfrac{625}{16} \\\\=\alpha^4+\beta^4+4*\alpha^3*\beta+6*\alpha^2*\beta^2+4*\alpha*\beta^3\\\\=\alpha^4+\beta^4+4*(\alpha*\beta)(\alpha^2+\beta^2)+6*\alpha^2*\beta^2\\\\\alpha^4+\beta^4=(\alpha+\beta)^4-4*(\alpha*\beta)(\alpha^2+\beta^2)-6*\alpha^2*\beta^2\\\\= \dfrac{625}{16} -4*\dfrac{1}{2} *\dfrac{21}{4} -6*(\dfrac{1}{2})^2 \\\\$