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diamong [38]
3 years ago
5

Write an equation for the line that is parallel to the given line and passes through the given point Y= 3x + 2; (1, 3)

Mathematics
1 answer:
IgorC [24]3 years ago
6 0

m = 3 is the slope of the given line; also its the slope of anything parallel to the given line

(x1,y1) = (1,3) is the given point the parallel line goes through

y - y1 = m(x-x1) .... point slope form

y - 3 = 3(x - 1) .... plug in the given values; solve for y

y - 3 = 3x - 3

y - 3+3 = 3x - 3 + 3

y = 3x + 0

y = 3x

Final Answer: y = 3x

side note: if you plugged in x = 1 it leads to y = 3 which confirms that (x,y) = (1,3) is on this parallel line.

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<u>Answer:</u>

Angle A = 39°

<u>Step-by-step explanation:</u>

We are given that there is a triangle ABC where a = 9, c = 5 and angle B = 120° and we are to find the measure of angle A.

But first we need to find the side b using the law of cosine:

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b^2 = 81 + 25 - 2*9*5*(-0.5)

b=\sqrt{151}

Now finding angle A using law of cosine:

cos(A) = \frac{b^2+c^2-a^2}{2b*c}

cos(A) = \frac{151+25-81}{2*12.29*5}

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Therefore, the measure of angle A = 39°.

7 0
3 years ago
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Ivan
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Step-by-step explanation:

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