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slamgirl [31]
4 years ago
8

A) Compare the y-intercepts of f(x) and g(x). Use complete sentences.

Mathematics
2 answers:
Lady bird [3.3K]4 years ago
8 0

Answer:


Step-by-step explanation:

a) y-intercept is when x=0


f(0)


=1/(0-3)


=-1/3


g(0)=0 from the graph


b) vertical asymptotes are vertical lines that f(x) and g(x) get close but do not exist there


Aneli [31]4 years ago
3 0

Answer:


Step-by-step explanation:

a) For the function f, the y-intercept is at (0, -1/3). For the function g as shown in the graph, the y-intercept is at (0,0) and it is higher than f.

b) For the function f, the vertical asymptote is at x=3. For the function g as shown in the graph, the vertical asymptote is at x=4 and is larger than that of f.


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The measures of the angles of a triangle are shown in the figure below. Solve for x.
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Answer:

Step-by-step explanation:

x=180-59-41

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3 years ago
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Find the solutions of the quadratic equation 14x^2+9x+10=014x
Vesnalui [34]

Answer:

Option B. x=-\frac{9}{28}(+/-)\frac{\sqrt{479}}{28}i

Step-by-step explanation:

we know that

The formula to solve a quadratic equation of the form ax^{2} +bx+c=0 is equal to

x=\frac{-b(+/-)\sqrt{b^{2}-4ac}} {2a}

in this problem we have

14x^{2}+9x+10=0

so

a=14\\b=9\\c=10

substitute in the formula

x=\frac{-9(+/-)\sqrt{9^{2}-4(14)(10)}} {2(14)}

x=\frac{-9(+/-)\sqrt{-479}} {28}

Remember that

i=\sqrt{-1}

substitute

x=\frac{-9(+/-)\sqrt{479}i} {28}  

x=-\frac{9}{28}(+/-)\frac{\sqrt{479}}{28}i

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3 years ago
Rapheal paid $624 for a camera during a 60% off sale. What was the cameras regular rice?
Nostrana [21]
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______________________________________________
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4 0
3 years ago
Anyone know the answer?? ​
Serggg [28]

Answer:

the second option

Step-by-step explanation:

in ax²+bx+c = 0:

x = \frac{-b+-\sqrt{b^2-4ac} }{2a}

subtract both sides by 6 to get to this form, as the right side will be left with 0

6x² + 8x - 6 = 0

here, the coefficient for x² (a) is 6, the coefficient for x (b) is 8, and the remaining number added on (c) is -6

plugging our numbers into the formula, we get

x = \frac{-8+-\sqrt{(-8)^2-4(6)(-6)} }{2(6)}\\= \frac{-8+-\sqrt{64-(-144)} }{12} \\= \frac{-8+-\sqrt{208} }{12} \\ = \frac{-8+\sqrt{208} }{12} or \frac{-8-\sqrt{208} }{12}\\= 0.53518375848 or -1.86851709182\\= approximately -1.87, 0.54

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2 years ago
Hii! please help i’ll give brainliest
Dafna11 [192]

Answer

east

Step-by-step explanation:

3 0
3 years ago
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