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Nadya [2.5K]
3 years ago
8

in converting 54 centimeters to inches what unit(omit the number) would you place in the numeration of your ratio? use plural fr

om in your answer remember that there 2.54 in 1 ichh
Mathematics
2 answers:
FrozenT [24]3 years ago
5 0

Answer:

just type inches int he box. It works trust me. took the test

dem82 [27]3 years ago
3 0

Answer:

To convert 54 centimeters to inches You need to divide it by 2.54 thus equaling 21.2598425197 inches approximately 21.26 inches

Step-by-step explanation:

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Leonard has 5 times as many stamps as Alison. Melissa has 7 more stamps than Leonard. If Alison has q stamps, how many stamps do
bija089 [108]
The answer is 35 just do 7x5
5 0
3 years ago
Find the area of a rectangle that is 16 3/5in. by 8 9/10
Alenkinab [10]
<h2>Greetings!</h2>

Answer:

Area is 147.74

Step-by-step explanation:

You need to recall that the equation for the area of a rectangle is:

Length * Width = area

So 16 3/5 * 8 9/10 = area

Rearrange so the whole numbers are being multiplied and the fractions are too:

We need to make the denominator same, this can be done by simply multiplying 3/5 by 2:

3/5 * 2 = 6/10

Now the two numbers can be written as 16.6 and 8.9.

Multiply both numbers by 10:

166 * 89 = 14774

Then divide this by 100 (two lots of division by 10)

14774 ÷ 1000 = 147.74

So the area of the rectangle is 147.74!


<h2>Hope this helps!</h2>
8 0
3 years ago
$5 PAYPAL + BRAINLIEST TO ANSWER THS
expeople1 [14]

Answer:

Quadratic Equation:

3x^2=2x +5

\text{Standard Form: } 3x^2-2x-5=0

From the standard form of a Quadratic Function, we get:

a=3,\:b=-2,\:c=-5

Discriminant:

\Delta=\left(-2\right)^2-4\cdot \:3\left(-5\right)

\Delta=\left(-2\right)^2+4\cdot \:3\cdot \:5

\Delta=64

From the discriminant, we conclude that the equation will have two real solutions.

State that:

b^2-4ac

b^2-4ac =0:\text{The equation has 1 real solution}

b^2-4ac >0:\text{The equation has 2 real solutions}

By the way, solving the equation given:

$x=\frac{2\pm\sqrt{64}}{2\cdot \:3}$

$x=\frac{2\pm\sqrt{64}}{6}$

$x=\frac{2\pm8}{6}$

$x_{1} =\frac{10}{6}=\frac{5}{3}  $

$x_{2}=\frac{-6}{6} =-1$

5 0
3 years ago
Which equation involves a prime quadratic and cannot be solved by factoring? A. x2 + 5x − 4 = 0 B. x2 − x − 6 = 0 C. x2 + 3x − 4
Damm [24]

Answer:

Option A

Step-by-step explanation:

We can try to factorize all the options one by one.

For A:

x^{2} +5x-4\\=> x^{2}+4x+x-4\\=>x(x+4)+1(x-4)

We can see that the quadratic expression cannot be solved by factorization as the factors at the end of factorization are not equal in both brackets. So Option A is the correct answer for the given question.

Moreover we can also note that all the other quadratic expressions can be factorized ..

8 0
3 years ago
Evaluate x - y - (-z) if x = -3, y = -7, and z = -9
IceJOKER [234]
It would be -6 x+9 i think.
3 0
2 years ago
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