Ask question

Ask question

All categories

Makovka662 [10]

3 years ago

15

I had $20.00 my mom gave me $10.00 my dad gave me 30.00 my aunt and uncle gave me $100.00 I had another $1.00 how much did I hav

e?

2 answers:

sweet-ann [11.9K]3 years ago

6 0

Answer:

$161

Step-by-step explanation:

Scilla [17]3 years ago

4 0

1.00000000091928828282 yeah yeah yeah

You might be interested in

The annual water usage in rockport increases at a rate of 10% every year as the town gets bigger. this year, the town used 6,740

Finger [1]

Answer:

<h2>46•18</h2>

Step-by-step explanation:

<h3> I=PRT/100</h3><h2> 6740×<u>1</u><u>0</u>×7</h2><h2> 100</h2><h2> 674×1×7</h2><h2> 4618</h2><h2>the nearest hundredth is a 46•18 this is my answer</h2>

6 0

2 years ago

The diagram shows a prisim

kramer

Because 2 squares equal a meter u have to do four up down one. (Front elevation)
Then just four by one square on second row down(side elevation)

5 0

2 years ago

An elliptical culvert is 3.5 feet tall and 6 feet wide. It is filled with water to a depth of 0.95 feet. Find the width of the s

maks197457 [2]

Answer:

$W_s \approx5.3$

Step-by-step explanation:

From the question we are told that

Height $H=3.5ft$

Weight $W= 6ft$

Depth $D=0.95ft$

Generally the equation for ellipses is given as

$\frac{x^2}{a^2} +\frac{y^2}{b^2} =1$

Where

$b=H/2\\b=3.5/2\\Therefore\\b=1.75\\a=W/2\\a=6/2\\Therefore\\a=3\\$

$\frac{x^2}{3^2} +\frac{y^2}{1.75^2} =1$

Generally to find y in the equation $\frac{x^2}{a^2} +\frac{y^2}{b^2} =1$

$y=-b+d$

$y=-1.75+0.95$

$y=-0.8$

Therefore

$\frac{x^2}{3^2} +\frac{(0.8)^2}{1.75^2} =1$

$\frac{x^2}{3^2} =1-\frac{(0.8)^2}{1.75^2}$

$\frac{x^2}{3^2} =1-0.2089795918$

$X^2 =3^2(1-0.2089795918)$

$X^2 =7.119183674$

$X =\sqrt{7.119183674}$

$X =2.66817984$

Therefore the width of the given stream is

$W_s=2.66817984*2$

$W_s=5.33635968$

$W_s \approx5.3$

3 0

3 years ago

What value of c is the rational expression below equal to zero? x-4/x-6

RSB [31]

Answer: x=4

Steps: (I am assuming your question has a typo in it and by "c" you meant "x")

The rational expression equals zero

$\frac{x-4}{x-6}=0$

only when the numerator equals 0 (the denominator cannot ever be zero):

$x-4 = 0 \\x = 4$

and that happens only for x=4

3 0

3 years ago

Each week, Heather’s company has $5000 in fixed costs plus an additional $250 for each system produced. The company is able to p

kvv77 [185]

The question is an illustration of composite functions.

Functions c(n) and h(n) are $\mathbf{c(n) = 5000 + 250n}$ and $\mathbf{n(h) = 5h}$
The composite function c(n(h)) is $\mathbf{c(n(h)) = 5000 + 1250h}$
The value of c(n(100)) is $\mathbf{c(n(100)) = 130000}$
The interpretation is: <em>"the cost of working for 100 hours is $130000"</em>

The given parameters are:

$5000 in fixed costs plus an additional $250
5 systems in one hour of production

<u>(a) Functions c(n) and n(h)</u>

Let the number of system be n, and h be the number of hours

So, the cost function (c(n)) is:

$\mathbf{c(n) = Fixed + Additional \times n}$

This gives

$\mathbf{c(n) = 5000 + 250 \times n}$

$\mathbf{c(n) = 5000 + 250n}$

The function for number of systems is:

$\mathbf{n(h) = 5 \times h}$

$\mathbf{n(h) = 5h}$

<u>(b) Function c(n(h))</u>

In (a), we have:

$\mathbf{c(n) = 5000 + 250n}$

$\mathbf{n(h) = 5h}$

Substitute n(h) for n in $\mathbf{c(n) = 5000 + 250n}$

$\mathbf{c(n(h)) = 5000 + 250n(h)}$

Substitute $\mathbf{n(h) = 5h}$

$\mathbf{c(n(h)) = 5000 + 250 \times 5h}$

$\mathbf{c(n(h)) = 5000 + 1250h}$

<u>(c) Find c(n(100))</u>

c(n(100)) means that h = 100.

So, we have:

$\mathbf{c(n(100)) = 5000 + 1250 \times 100}$

$\mathbf{c(n(100)) = 5000 + 125000}$

$\mathbf{c(n(100)) = 130000}$

<u>(d) Interpret (c)</u>

In (c), we have: $\mathbf{c(n(100)) = 130000}$

It means that:

The cost of working for 100 hours is $130000

Read more about composite functions at:

brainly.com/question/10830110

5 0

3 years ago