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PolarNik [594]
3 years ago
7

Margo is given the graph below. What type of graph is shown, and what is the growth factor?

Mathematics
2 answers:
aleksandr82 [10.1K]3 years ago
8 0

Answer:

D. exponential function; growth factor of 4

Step-by-step explanation:

Rus_ich [418]3 years ago
5 0

can you give the graph or the link


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Convert the following fraction into a decimal.
ira [324]

Answer:

0.525

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2 years ago
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Spiral Homework<br>Chapter 3 Lesson 5<br>-ach expression.<br>2. 3(-3) + 17<br>5. -21(3) + (-19)​
tankabanditka [31]

2. 3(-3)+17=8

3. -21(3) + (-19)=-82​

Step-by-step explanation:

We need to solve the following expressions.

2. 3(-3)+17

Solving we get:

3(-3)+17\\=-9+17\\=+8

5. -21(3)+(-19)​

Solving we get:

-21(3) + (-19)\\=-63+(-19)\\=-63-19\\=-82

Keywords: Integers

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3 years ago
Correlation Coefficients. Image attached for the problem.<br><br> A. 11<br> B. 9<br> C. 3<br> D. 5
andreyandreev [35.5K]

Answer:

A

Step-by-step explanation:

y bar basically means the average of the y-values.

To get the average, we add up all the y-values in the table and divide by the total number of values (here we have 5 values). Hence,

y bar = \frac{5+7+10+15+18}{5}=11

correct answer is A

8 0
3 years ago
The managers of 21 supermarkets counted the number of cars in their parking lots on the same day. The results are shown in the l
mixer [17]

The IQR is 42.5

Step-by-step explanation:

Interquartile range is the difference of third and first quartile.

First of all we have to find the median for that purpose the data has to be arranged in ascending order. The data is already in ascending order.

As the number of values are odd

n=21

The median will be: (\frac{n+1}{2}) th\ term

Putting n=21

(\frac{21+1}{2})th\ term\\=(\frac{22}{2})th\ term\\= 11th\ term

The 11th term is 133

So median = 133

Now the data is divided into two halves

One is: 98, 100, 101, 102, 108, 109, 111,118, 129, 132

2nd is: 135, 135, 145, 146, 146, 156, 170 176, 180, 180

Q1 will be the median of first half and Q3 will be the median of 2nd half.

As now the halves contain even number of values, the medians will be the average of middle two values

<u>For First Half:</u>

98, 100, 101, 102, <u>108, 109</u>, 111,118, 129, 132

Q_1 = \frac{108+109}{2}\\Q_1 = \frac{217}{2}\\Q_1 = 108.5

<u>For Second Half:</u>

135, 135, 145, 146, 146, 156, 170 176, 180, 180

Q_2 = \frac{146+156}{2}\\Q_2 = \frac{302}{2}\\Q_2 = 151

Now

<u>Interquartile Range:</u>

IQR = Q_3-Q_1\\= 151-108.5\\=42.5

Hence,

The IQR is 42.5

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7 0
3 years ago
Which of these sums is less than 1
natka813 [3]
The answer is B, 1/3+1/8

—Evidence—
•] I added all of the options and got an answer of 1.35 to 1.5 and one of the choices had a answer of 0.4583 which was option B.
8 0
3 years ago
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