Answer:
UV=29
Step-by-step explanation:
In right triangles AQB and AVB,
∠AQB = ∠AVB ...(i) {Right angles}
∠QBA = ∠VBA ...(ii) {Given that they are equal}
We know that sum of all three angles in a triangle is equal to 180 degree. So wee can write sum equation for each triangle
∠AQB+∠QBA+∠BAQ=180 ...(iii)
∠AVB+∠VBA+∠BAV=180 ...(iv)
using (iii) and (iv)
∠AQB+∠QBA+∠BAQ=∠AVB+∠VBA+∠BAV
∠AVB+∠VBA+∠BAQ=∠AVB+∠VBA+∠BAV (using (i) and (ii))
∠BAQ=∠BAV...(v)
Now consider triangles AQB and AVB;
∠BAQ=∠BAV {from (v)}
∠QBA = ∠VBA {from (ii)}
AB=AB {common side}
So using ASA, triangles AQB and AVB are congruent.
We know that corresponding sides of congruent triangles are equal.
Hence
AQ=AV
5x+9=7x+1
9-1=7x-5x
8=2x
divide both sides by 2
4=x
Now plug value of x=4 into UV=7x+1
UV=7*4+1=28+1=29
<u>Hence UV=29 is final answer.</u>
Answer:
A. 29i
Step-by-step explanation:
Step 1: Plug in given variables
(2 - 5i)(2 + 5i)i
Step 2: Difference of squares (expand)
(4 - 25i²)i
Step 3: Imaginary numbers rules
(4 - 25(-1))i
Step 4: Combine like terms
(4 + 25)i
(29)i
Your final answer will be 29i
10 1/3= 31/3
31/3= 93/9
11 5/9= 104/9
93/9 + 104/9 = 197/9
197/9= 21 8/9
your answer is 21 & 8/9
Good Luck
XD
I would say the object will float because the density of water is 999.99kg/m which is slightly less than 1g but still more than the object.