If f(x)=x^3-9x^2+11x+21f(x)=x 3 −9x 2 +11x+21 and x-3x−3 is a factor of f(x)f(x), then find all of the zeros of f(x)f(x) algebra
ically.
1 answer:
Answer:
x = -1, 3, and 7
Step-by-step explanation:
Using grouping:
f(x) = x³ − 9x² + 11x + 21
f(x) = x³ − 9x² + 18x − 7x + 21
f(x) = x (x² − 9x + 18) − 7 (x − 3)
f(x) = x (x − 6) (x − 3) − 7 (x − 3)
f(x) = (x² − 6x) (x − 3) − 7 (x − 3)
f(x) = (x² − 6x − 7) (x − 3)
f(x) = (x + 1) (x − 7) (x − 3)
To use long division, see the picture.
The zeros are x = -1, 3, and 7.
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Solving the equation we get value of p = -4
Step-by-step explanation:
We need to find the value of p in the equation
Solving to find value of p:
So, solving the equation we get value of p = -4
Keywords: Solving Equations
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Answer:
a) 0.75
b)5.05
c)0.02
Step-by-step explanation:
a)
P(Y>5)=?
This part is solved in the given picture.
b)
The mean of a uniform distribution is (a+b)/2.
Where a=4.95 , b=5.15.
E(Y)=(4.95+5.15)/2
E(Y)=10.1/2
E(Y)=5.05.
c)
The variance of a uniform distribution is (b-a)²/2.
V(Y)=(5.15-4.95)²/2
V(Y)=0.2²/2
V(Y)=0.04/2
V(Y)=0.02.
