Answer:
i dont know maybe you should search google. best of Luck
Step-by-step explanation:
Answer:
Let X the random variable that represent the number of emails from students the day before the midterm exam. For this case the best distribution for the random variable X is
The probability mass function for the random variable is given by:

The best answer for this case would be:
C. Poisson distribution
Step-by-step explanation:
Let X the random variable that represent the number of emails from students the day before the midterm exam. For this case the best distribution for the random variable X is
The probability mass function for the random variable is given by:
And f(x)=0 for other case.
For this distribution the expected value is the same parameter
And for this case we want to calculate this probability:

The best answer for this case would be:
C. Poisson distribution
13 + 23 · (19 - 7)
Do the parentheses first.
13 + 23 · (12)
Now do multiplication.
13 + 276 = 289
The answer is D) 289.
Answer:

Step-by-step explanation:

<em>hope</em><em> </em><em>this</em><em> </em><em>helps</em>
<em>brainliest</em><em> </em><em>appreciated</em>
<em>good</em><em> </em><em>luck</em><em>!</em><em> </em><em>have</em><em> </em><em>a</em><em> </em><em>nice</em><em> </em><em>day</em><em>!</em>
Answer:
24
Step-by-step explanation: