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zysi [14]
3 years ago
13

What is the answer to this question can you please answer right

Mathematics
1 answer:
Arada [10]3 years ago
6 0
On Monday she made 50 throws.
On Tuesday she made 56 throws.

a) The increase is just how much more she made the next day.
56 - 50 = 6
She had an increase of 6 free throws.

b) To find the percent increase, all you do is divide the two numbers.
56/50 = 1.12
To change that into a percentage, either multiply it by 100 or move the decimal point two places to the right.
1.12 × 100 = 112
She had a 112% increase in her free throws.

The answer is:
D. 6; 112%
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A company dyes two sizes of rugs. A small rug requires 2 hours for dyeing and a medium-size rug requires 3 hours for dyeing. The
TiliK225 [7]
X + y > = 15.....this is saying that small rugs (x) + medium rugs (y) when made, are greater then or equal to 15...because they have to make at least 15

and since small rugs take 2 hrs......2x....and medium rugs take 3 hrs....3y...and they have to be made in less then 60 hrs...
2x + 3y < 60 <=== ur answer


7 0
3 years ago
How to write 16,208.59 in word form
IrinaK [193]

Answer:

Sixteen thousand, two hundred eight and fifty-nine hundredths.

I hope this helps! :)

8 0
3 years ago
(02.03)
RoseWind [281]

Answer:

It's the one under the one you have selected.

Step-by-step explanation:

7:2

14:4

28:8

56:16

Divide the first number by 7 then multiply it by 2.

Example: 56/7=8, 8*2=16 so it's correct.

4 0
3 years ago
Read 2 more answers
Suppose the mean income of firms in the industry for a year is 95 million dollars with a standard deviation of 5 million dollars
GuDViN [60]

Answer:

Probability that a randomly selected firm will earn less than 100 million dollars is 0.8413.

Step-by-step explanation:

We are given that the mean income of firms in the industry for a year is 95 million dollars with a standard deviation of 5 million dollars. Also, incomes for the industry are distributed normally.

<em>Let X = incomes for the industry</em>

So, X ~ N(\mu=95,\sigma^{2}=5^{2})

Now, the z score probability distribution is given by;

         Z = \frac{X-\mu}{\sigma} ~ N(0,1)

where, \mu = mean income of firms in the industry = 95 million dollars

            \sigma = standard deviation = 5 million dollars

So, probability that a randomly selected firm will earn less than 100 million dollars is given by = P(X < 100 million dollars)

    P(X < 100) = P( \frac{X-\mu}{\sigma} < \frac{100-95}{5} ) = P(Z < 1) = 0.8413   {using z table]

                                                     

Therefore, probability that a randomly selected firm will earn less than 100 million dollars is 0.8413.

5 0
3 years ago
Solve the equation. Check for extraneous answers
Lady bird [3.3K]
The answer is A i hope this helps 
7 0
3 years ago
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