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2 years ago

Using Order of Operations (PEMDAS), solve the following two expressions. Show all steps.

Mathematics

2 answers:

aksik [14]2 years ago

8 0

Answer:

Multiple: 3 * 5 = 15

Add: 7 + the result of step No. 1 = 7 + 15 = 22

Divide: 4 / 2 = 2

Subtract: the result of step No. 2 - the result of step No. 3 = 22 - 2 = 20

Add: the result of step No. 4 + 3 = 20 + 3 = 23

Add: 7 + 3 = 10

Multiple: the result of step No. 1 * 5 = 10 * 5 = 50

Divide: 4 / 2 = 2

Subtract: the result of step No. 2 - the result of step No. 3 = 50 - 2 = 48

Add: the result of step No. 4 + 3 = 48 + 3 = 51

mart [117]2 years ago

4 0

9514 1404 393

Answer:

a) 23

b) 26

Step-by-step explanation:

a) Perform the multiplication and division first, then the addition.

7 + 3·5 -4÷2 +3

= 7 +15 -2 +3

= 23

b) Evaluate parentheses first, then the rest of it. The multiplication and division are done before the addition at the same level.

((7 +3)·5 -4)÷2 +3

= (10·5 -4)÷2 +3

= (50 -4)÷2 +3

= 46÷2 +3

= 23 +3

= 26

_____

Additional comment

An appropriate calculator can evaluate these for you. The Go.ogle calculator reliably follows the order of operations. You can use an asterisk (*) for multiplication with that calculator.

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Read 2 more answers

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tankabanditka [31]

Answer:

$(a)\ AB = \frac{7}{\sin (B)}$ $\to Yes$

$(b)\ AB = \frac{24}{\cos (B)}$ $\to Yes$

$(c)\ AB = \frac{24}{\cos (A)}$ $\to No$

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Step-by-step explanation:

Given

$BC =24$

$AC = 7$

Required

Select Yes or No for the given options

$(a)\ AB = \frac{7}{\sin (B)}$ $\to Yes$

Considering the sine of angle B, we have:

$\sin(B) = \frac{Opposite}{Hypotenuse}$

$\sin(B) = \frac{7}{AB}$

Make AB, the subject

$AB = \frac{7}{\sin(B)}$

$(b)\ AB = \frac{24}{\cos (B)}$ $\to Yes$

Considering the cosine of angle B, we have:

$\cos(B) = \frac{Adjacent}{Hypotenuse}$

$\cos(B) = \frac{24}{AB}$

Make AB the subject

$AB = \frac{24}{\cos(B)}$

$(c)\ AB = \frac{24}{\cos (A)}$ $\to No$

Considering the cosine of angle B, we have:

$\cos(A) = \frac{Adjacent}{Hypotenuse}$

$\cos(A) = \frac{7}{AB}$

Make AB the subject

$AB = \frac{7}{\cos(A)}$

$(d)\ AB = \frac{7}{\cos (A)}$ $\to Yes$

This has been shown in (c) above

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