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Roman55 [17]
4 years ago
11

Plz help I’m confused can someone help with one ,three and 4 oh and 2 I’ll give you 22 points plz help fast thank you plz plz ex

plain for 1 plz

Mathematics
1 answer:
noname [10]4 years ago
8 0

1. 783*23=18009, so it is 18009miles^2

2. Triangle

3. B is your variable

4. -60


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2(8 + t)* 6 when s = 3 and t = 2.
jarptica [38.1K]

Answer:

120

Step-by-step explanation:

Plug in variables with numbers

2(8+2)*6

2(10)*6

20*6

120

Please mark brainliest!

4 0
3 years ago
Help me with these please​
olchik [2.2K]

Step-by-step explanation:

(1) y = x e^(x²)

Take derivative with respect to x:

dy/dx = x (e^(x²) 2x) + e^(x²)

dy/dx = 2x² e^(x²) + e^(x²)

dy/dx = (2x² + 1) e^(x²)

Take derivative with respect to x again:

d²y/dx² = (2x² + 1) (e^(x²) 2x) + (4x) e^(x²)

d²y/dx² = (4x³ + 2x) e^(x²) + 4x e^(x²)

d²y/dx² = (4x³ + 6x) e^(x²)

Substitute:

d²y/dx² − 2x dy/dx − 4y

= (4x³ + 6x) e^(x²) − 2x (2x² + 1) e^(x²) − 4x e^(x²)

= 4x³ + 6x − 2x (2x² + 1) − 4x

= 4x³ + 6x − 4x³ − 2x − 4x

= 0

(2) y = sin⁻¹(√x)

sin y = √x

sin²y = x

Take derivative with respect to x:

2 sin y cos y dy/dx = 1

sin(2y) dy/dx = 1

dy/dx = csc(2y)

Take derivative with respect to x again:

d²y/dx² = -csc(2y) cot(2y) 2 dy/dx

d²y/dx² = -2 csc²(2y) cot(2y)

Substitute:

2x (1 − x) d²y/dx² + (1 − 2x) dy/dx

= 2 sin²y (1 − sin²y) (-2 csc²(2y) cot(2y)) + (1 − 2 sin²y) csc(2y)

Use power reduction formula:

= (1 − cos(2y)) (1 − ½ (1 − cos(2y))) (-2 csc²(2y) cot(2y)) + (1 − (1 − cos(2y))) csc(2y)

= (1 − cos(2y)) (1 − ½ + ½ cos(2y)) (-2 csc²(2y) cot(2y)) + cos(2y) csc(2y)

= (1 − cos(2y)) (½ + ½ cos(2y)) (-2 csc²(2y) cot(2y)) + cot(2y)

= (cos(2y) − 1) (1 + cos(2y)) csc²(2y) cot(2y) + cot(2y)

= (cos²(2y) − 1) csc²(2y) cot(2y) + cot(2y)

= -sin²(2y) csc²(2y) cot(2y) + cot(2y)

= -cot(2y) + cot(2y)

= 0

8 0
3 years ago
PLEASE ANSWER AS QUICK AS POSSIBLE
Lady_Fox [76]

Answer:

  (a)  h^-1(x) = (x+6)/6

Step-by-step explanation:

The inverse relation can be found by solving for y: x = h(y).

<h3>Solution</h3>

  x = h(y) . . . . . the inverse relation

  x = 6y -6 . . . . . use the function definition

  x +6 = 6y . . . . add 6

  (x +6)/6 = y . . . . divide by 6

The inverse function is ...

  \boxed{h^{-1}(x)=\dfrac{x+6}{6}}

4 0
2 years ago
Vaimiti walks at a constant pace of 1.1 m/s and takes 25 minutes to get to school.
Temka [501]

Solution:

<u>Note that:</u>

  • Speed = Distance/Time
  • Vaimiti speed = 1.1 m/s
  • Jabril speed = 1.3 m/s

<u>Converting the time (minutes to seconds) for Vaimiti to reach school:</u>

  • Vaimiti's time to reach school: 25 minutes = 25 x 60 seconds
  • => Vaimiti's time to reach school: 1500 seconds

<u>Converting the time (minutes to seconds) for Jabril to reach school:</u>

  • Jabril's time to reach school: 30 minutes = 30 x 60 seconds
  • => Jabril's time to reach school: 1800 seconds

<u>Finding the distance of Vaimiti:</u>

  • Speed = Distance/Time

Important: <em>The distance will be in meters since the speed units is </em><u><em>meters</em></u><em>/seconds.</em>

  • => 1.1 meters/second = Distance/1500
  • => 1.1 x 1500 = Distance
  • => 1650 meters = Distance (In meters)

<u>Finding the distance of Jabril:</u>

  • Speed = Distance/Time

Important: <em>The distance will be in meters since the speed units is </em><u><em>meters</em></u><em>/seconds.</em>

  • 1.3 meters/second = Distance (In meters)/1800 seconds
  • => 1.3 x 1800 = Distance (In meters)
  • => 2340 meters = Distance (In meters)

This can lead to two possible solutions:

Possible solution #1:

<u>Finding the difference between the two distances:</u>

  • 2340 meters - 1650 meters = Difference (In meters)
  • => 690 meters

Possible solution #2:

The difference between the <u>distances they walked</u> is that Jabril walked <u>faster</u> than Vaimiti, but Vaimiti reached <u>school</u> earlier than Jabril because the <u>walking distance</u> for Vaimiti is less than the <u>walking</u> <u>distance</u> for Jabril.

Hoped this helped!

6 0
3 years ago
Read 2 more answers
In the 2011 season, drew brees of the New Orleans saints completed 468 passes. This was 71.2% of his attempts. How many attempts
mariarad [96]

He complete 468 passes and this represents 71.2% of his attempted passes. Set this up as a ratio. 468       71.2----  =  ------ x          100 cross multiply and solve46800 = 71.2xx = 657.3He attempted 657 passes.
8 0
4 years ago
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