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3 years ago

4. A 16-piece orchestra wants to choose one

Mathematics

2 answers:

LUCKY_DIMON [66]3 years ago

8 0

Answer:

1/12

Step-by-step explanation:

Out of 16, 4 can’t be chosen which leaves 12 to choose from, Itzhak being ONE of them.

So that’s one out of twelve (1/12)

pishuonlain [190]3 years ago

5 0

Answer:

1/12

Step-by-step explanation:

subtract the four soloists who can't be chosen from the total musicians

16-4=12

Itzhak is one person out of 12 who could be chosen to speak

Also the question is annoying because nobody calls an orchestra with 16 people a "16 piece orchestra"

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Answer:

The answer is, q = 16.

Step-by-step explanation:

1) Divide both sides by 3.

$q - 7 = \frac{27}{3}$

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2 years ago

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<img src="https://tex.z-dn.net/?f=%28-1%7B2%7D%7B3%7D%20%29x%5E%7B3%7D" id="TexFormula1" title="(-1{2}{3} )x^{3}" alt="(-1{2}{3}

Alex_Xolod [135]

After talking with you here are two different options I think you are trying to ask:

~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~

If you are talking about: $(\frac{-12}{3}) ^{3}$

Answer: -62

Explanation:

PEMDAS tells us we need to do the exponent first:

-12³ = (-12)³ = -1728

The parentheses are important so you cube the negative sign as well!

3³ = 27

-1728 / 27 = -62

$(\frac{-12}{3}) ^{3}$ simplified is -62

~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~

If you are talking about (-1 $\frac{2}{3}$ )³

Answer: - $\frac{125}{27}$

Explanation:

First, let us turn -1 and two thirds into a mixed number:

Ignoring the negative for now, we can 1 times 3 is 3. 3 plus 2 is 5. 5/3 is 5/3. Adding in the negative we get $-\frac{5}{3}$

To cube it we must do:

( $-\frac{5}{3}$ )( $-\frac{5}{3}$ )( $-\frac{5}{3}$ )

3 times 3 (9) times 3 is 27

5 times 5 (25) times 5 is 125

So we have 125/27

For the negative, we have three - - -

Two cancel each other out, and we are left with one (-) so our answer is negative

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2 years ago

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