Answer:
Ladder reaches 9.76 high.
Step-by-step explanation:
From the figure attached,
Ac is the ladder which reaches at the point A when leans against the side of a house.
Length of the ladder = 10 feet
Distance of the ladder form the base of a house = 2.2 ft
By Pythagoras theorem,
AC² = AB² + BC²
(10)² = h² + (2.2)²
h² = 100 - 4.84
h = √95.16
h = 9.755 feet
≈ 9.76 feet
Therefore, the ladder reaches the 9.76 high.
g(x) =f(x) +3
given f(x) =3x
i.e. g(x) =3x+3
For F(x) to be same as g(x)
3 must be added to f(x)
i.e. h(x) =3x+3
->h(x)= 3x +3(1)
-> h(x) = f(x) +f(1)
-> h(x) =f(x+1)
Hence Option (a) is your answer...
Hope it helps...
Regards
Leukonov/Olegion
The initial height is .5 m. If the ball only reaches 52% of the previous max height, then after the third bounce you have:
.5 x (.52)^3=0.070304 meters as the height of the ball
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