An alternating series
converges if
is monotonic and
as
. Here
.
Let
. Then
, which is positive for all
, so
is monotonically increasing for
. This would mean
must be a monotonically decreasing sequence over the same interval, and so must
.
Because
is monotonically increasing, but will still always be positive, it follows that
as
.
So,
converges.
The equation that has an infinite number of solutions is 
<h3>How to determine the equation?</h3>
An equation that has an infinite number of solutions would be in the form
a = a
This means that both sides of the equation would be the same
Start by simplifying the options
3(x – 1) = x + 2(x + 1) + 1
3x - 3 = x + 3x + 2 + 1
3x - 3 = 4x + 3
Evaluate
x = 6 ----- one solution
x – 4(x + 1) = –3(x + 1) + 1
x - 4x - 4 = -3x - 3 + 1
-3x - 4 = -3x - 2
-4 = -2 ---- no solution
2x + 3 = 2x + 1 + 2
2x + 3 = 2x + 3
Subtract 2x
3 = 3 ---- infinite solution
Hence, the equation that has an infinite number of solutions is
Read more about equations at:
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<u>Complete question</u>
Which equation has infinite solutions?
3(x – 1) = x + 2(x + 1) + 1
x – 4(x + 1) = –3(x + 1) + 1
You need to isolate the variable <em>h</em>.
1) Subtract both sides by 2.
-4h + 2 = 18
-4h + 2 - 2 = 18 - 2
-4h = 16
2) Divide both sides by -4 (the coefficient).
(-4h) / -4 = 16 / -4
h = -4
