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murzikaleks [220]
3 years ago
6

The diagonals of a rhombus are 12 in. and 16 in. long. The length of a side of the rhombus is 10 in. What is the height of the r

hombus? Explain how you found your answer.
Mathematics
1 answer:
iris [78.8K]3 years ago
3 0
If d₁ and d₂ are the lengths of the diagonals, the area is given by
.. A = (1/2)*d₁*d₂
.. A = (1/2)*(12 in)*(16 in)
.. A = 96 in²

If b is the base and h is the height, the area is given by
.. A = b*h
We know the values of A and b, so
.. 96 in² = (10 in)*h
.. (96 in²)/(10 in) = h = 9.6 in

The height is 9.6 in.
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The points (-10, 0) and (-5, 3) fall on a particular line. What is it’s equation in slope-intercept form?
yaroslaw [1]

Answer:

  y = 3/5x + 6

Step-by-step explanation:

When given two points, it is convenient to start with the 2-point form of the equation of a line, then rearrange it to the form needed for the problem. For points (x1, y1) and (x2, y2), the equation is ...

  y = (y2 -y1)/(x2 -x1)·(x -x1) +y1

Filling in the given point coordinates, this is ...

  y = (3 -0)/(-5 -(-10))·(x -(-10)) + 0

  y = 3/5(x +10)

  y = (3/5)x + 6

5 0
3 years ago
Supposef(0) = 2 and 2 ≤ f '(x) ≤ 7for all x in the interval [−5, 5]. determine the greatest and least possible values of f(2).le
IgorC [24]

If the slope of the function is 2, the amount it can change over the interval 0–2 is

... 2×2 = 4 units

If the slope is 7, the amount it can change over the interval 0–2 is

... 2×7 = 14 units


The least possible value of f(2) is 2+4 = 6.

The greatest possible value of f(2) is 2+14 = 16.

7 0
3 years ago
True or False: (x + 3)2 = x2 + 9
malfutka [58]

Answer:

false

Step-by-step explanation:

3 0
3 years ago
Pls help plsssssssssssssssssssssss
iren [92.7K]

Answer:

It would be 14 because since each book is 3.5cm thick times that by 4 and get 14.

8 0
2 years ago
Read 2 more answers
5cosx -2sin(x/2) +7=0<br>Help me to find x step by step<br>pls​
miskamm [114]

Answer:

x = 180

Step-by-step explanation:

First, you need to know

1. Double-angle formula:

cos(2x) = cos^{2}x - sin^{2}x

2. Pythagorean identity:

cos^{2}x + sin^{2}x = 1

Back to your problem, replacing the variable by the above:

5cosx-sin\frac{x}{2}+7 = 0

5(cos^{2}\frac{x}{2}-sin^{2}\frac{x}{2}) - 2sin\frac{x}{2} + 7 = 0 By Double-angle formula

5(1 - 2sin^{2}\frac{x}{2}) - 2sin\frac{x}{2} + 7 = 0 By Pythagorean identity

Given y = \frac{x}{2}

5(1-2sin^{2}y) - 2siny + 7 = 0

10sin^{2}y+2siny-12=0

5sin^{2}y+siny-6=0

(5siny + 6)(siny - 1)=0, we know -1 < sinx < 1, for every x ∈ R

siny = 1, y =90

y = \frac{x}{2}

x = 180

8 0
3 years ago
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