The diagonals of a rhombus are 12 in. and 16 in. long. The length of a side of the rhombus is 10 in. What is the height of the r
1 answer:
You might be interested in
a) The probability that both John and Jane watch the show is 0.12.
b.The probability that Jane watches the show, given that John does is 0.1714.
c)They do watch show independent of each other.
Step-by-step explanation:
Here, as given in the question:
Probability that John watches a certain show = 0.7 ⇒ P(J) = 0.7
Probability that Jane watches a certain show = 0.3 ⇒ P(Je) = 0.3
Probability that John watches a certain show given Jane watches it to
= 0.4 ⇒ P(J/Je) = 0.4
a. ) Here, we need to find the probability of both Jane and John watching a show , P(J∩Je)
Now, by BAYES THEOREM:
Hence the probability that both John and Jane watch the show is 0.12.
b.) The probability that Jane watches the show, given that John does is P(J/Je)
By BAYES Theorem:
Hence, the probability that Jane watches the show, given that John does is 0.1714.
c) As we can see P(Jane ∩ John) = 0.12
So, the probability of both of them seeing the show TOGETHER is 0.12.
Hence, they do watch show independent of each other and the probability of doing that is 1.0.12 = 0.88
Answer:
80%
Step-by-step explanation:
According to the given data, the numbers 0 through 6 represent students who sent a text yesterday while the numbers 7 through 9 represent students who did not send a text yesterday.
Based on this key, we will calculate the number of students who sent the text yesterday and the number of students who did not sent the text yesterday.
The given data is: 62072, 34570, 80983, 04292, 83150, 36330, 96268, 14077, 77985, 13511
For each group we will identify how many students sent the text and how many students did not. According to the key, a number from 0 to 6 will be counted as a student who sent the text and a number from 7 to 9 will be counted as a student who did not send the text. Students who did not sent the text are made bold in the groups below.
62072: 4 students sent the text, 1 did not
34570: 4 students sent the text, 1 did not
80983: 2 students sent the text, 3 did not
04292: 4 students sent the text, 1 did not
83150: 4 students sent the text, 1 did not
36330: All 5 students sent the text
96268: 3 students sent the text, 2 did not
14077: 3 students sent the text, 2 did not
77985: 1 student sent the text, 4 did not
13511: All 5 students sent the text
We need to find the probability that 3 or more of a group of 5 students randomly selected will send a text today.
From the given groups, the number of groups where 3 or more students sent a text = 8
This represents our number of favorable or desired outcomes.
Total number of possible outcomes is the total number of groups = 10
Since, probability is defined as the ratio of number of favorable outcomes to total number of outcomes, based on the simulated data the probability that 3 or more of a group of 5 students randomly selected will send a text today will be =
Thus, based on the simulated data there is 80% probability that 3 or more of a group of 5 students randomly selected will send a text today