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4 years ago

7

9) 15k + 20 – 10k = 10

1 answer:

Mashutka [201]4 years ago

6 0

Answer:

k=-2

Step-by-step explanation:

You have to bring k itself and make it to a coefficient of 1 using algebra.

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Ryan earns $5 for each small dog he walks and $8 for each large dog he walks. Today he walked 8 dogs and made a total of $55. Ho

Sunny_sXe [5.5K]

Let L and S be the number of large and small dogs respectively.

L+S=8 so we can say L=8-S

5S+8L=55, using L found above in this equation yields:

5S+8(8-S)=55

5S+64-8S=55

-3S+64=55

-3S=-9

S=3, since L=8-S

L=5

So Ryan walked 3 small dogs and 5 large dogs.

5 0

3 years ago

Read 2 more answers

If a = 9-4√5 find the value of a - 1/a

e-lub [12.9K]

The solution is attached
the answer is -8√5

7 0

4 years ago

(3x) (4x) = <br> A. – x <br> B. 7x <br> C. 12x <br> D. 12x² <br> E. none of these

Mice21 [21]

$\huge\text{Hey there!}$

$\large\textbf{Equation: }$

$\large\textsf{(3x)(4x)}$

$\large\textbf{Solving:}$

$\large\textsf{(3x)(4x)}$

$\large\textsf{= 3x} * \large\textsf{4x}$

$\large\textbf{Combine the like terms:}$

$\large\textsf{(3x * 4x)}$

$\large\textsf{= 3x * 4x}$

$\large\textsf{= 12x}^2$

$\large\textbf{Therefore, your answer should be: }$

$\huge\boxed{\frak{Option\ D. 12\mathsf{x}^2}}\huge\checkmark$

$\huge\text{Good luck on your assignment \& enjoy your day!}$

~ $\frak{Amphitrite1040:)}$

8 0

2 years ago

How many different arrangements of 3 letters can be formed if the first letter must be w or k (repeats of letters are allowed)

jekas [21]

Answer:

Total 1352 different arrangements can be formed.

Step-by-step explanation:

Total number of letters is 26 (a to z).

We need to find the arrangements of 3 letters

It is given that the first letter must be w or k and repetition of letters are allowed.

Since first letter can be w or k, therefore the possibilities for first letter is 2.

Repetition of letters are allowed and any letter can be formed in place of second and third letter.

So, the possibilities for second letter is 26 and possibilities for third letter is 26.

Total possibilities of arrangements of 3 letters is

$P=2\times 26\times 26=1352$

Therefore total 1352 different arrangements can be formed.

5 0

3 years ago

Help me please with the question in the photo

Marianna [84]

Answer:

i think that the correct answer would be the second one

Step-by-step explanation:

i am so so sorry if the answer is wrong

hope this helps

plz mark brainliest

and plz hit the thanks button

8 0

3 years ago