A - 2x^2 + 2x - 2
To find this, set up the equation:
(-x^2 + 6x - 1) + ( 3x^2 - 4x - 1)
With this, you need to combine like terms while taking into consideration the addition sign.
-x^2 + 3x^2 = 2x^2
6x + - 4x = 2x
- 1 + - 1 = - 2
Hope this helps!
<span>0.53(3)+5 = 1.59 + 5 = 6.59 when n = 3
</span>0.53(-3)+5 = -1.59 + 5 = 3.41 when n = -3
Step-by-step explanation:

Answer:
ab - ac + db - dc
Step-by-step explanation:
you distribute the variables inside the parenthesis
Answer:
a =1 and a=4.
Step-by-step explanation:
The function is

If we want f(x) to be continuous the denominator needs to be different to 0, otherwise f(x) will be indeterminate.
Now, for a a positive real we have that
will annulate the denominator, i.e
. But, if a = 1 we have:

so, the value
won't annulate the denominator.
Now, for a = 4 we have:

so, the value
won't annulate the denominator.
In conclusion, for a=1 or a=1, the function will be continuos for all real numbers, since the denominator will never be 0.