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Maru [420]
3 years ago
13

Which of the following numbers is the 8th term of sequence

Mathematics
1 answer:
OverLord2011 [107]3 years ago
5 0

Answer:

16

Step-by-step explanation:

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The sum of q and 5 whoever answers this please explain and answer
jok3333 [9.3K]

Answer:

It will be "q+5"

Step-by-step explanation:

When you add a number and a letter you just leave them like that. If you would to have a number multiplying a letter like "5q" and something else like "3q" when you add them together you will get "5q+3q=8q" In this case you can add them together because the number is multiplying the letter.

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Can someone give me an explanation to hyperbola
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Answer:

its a symmetrical open curve formed by the intersection of a circular cone with a plane at a smaller angle with its axis than the side of the cone.

Step-by-step explanation:

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2 years ago
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Is 0.95x 10^8 a scientific notation
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1 year ago
Simplify 15 + 6(x + 1).
Nikolay [14]
15 + 6(x + 1)

First, expand to get rid of parentheses. 
15 + 6x + 6
Second, simplify. Keep your 6x and add 15 + 6.
6x + 21

Answer: 6x + 21

6 0
3 years ago
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What is the following sum? Assume x > 0 and y > 0 sqrt x^2y^2+2 sqrt x^3y^4+xy sqrt y
Gwar [14]

Answer:

xy(1+2y\sqrt{x}+\sqrt{y})

Step-by-step explanation:

Given expression,

\sqrt{x^2y^2}+2\sqrt{x^3y^4}+xy\sqrt{y}

=(x^2y^2)^\frac{1}{2} + 2(x^3y^4)^\frac{1}{2} + xy\sqrt{y}

\because (\sqrt{x}=x^\frac{1}{2})

=(x^2)^\frac{1}{2} (y^2)^\frac{1}{2} + 2(x^3)^\frac{1}{2} (y^4)^\frac{1}{2} + xy\sqrt{y}

(\because (ab)^n=a^n b^n)

=x^{2\times \frac{1}{2}} y^{2\times \frac{1}{2}} + 2(x^{3\times \frac{1}{2}})(y^{4\times \frac{1}{2}})+xy\sqrt{y}

\because (a^n)^m=a^{mn}

=x^1 y^1 + 2x^{1\frac{1}{2}} y^2 + xy\sqrt{y}

=xy+2x.(x)^\frac{1}{2} y^2 + xy\sqrt{y}

=xy+2xy^2\sqrt{x}+xy\sqrt{y}

=xy(1+2y\sqrt{x}+\sqrt{y})

8 0
3 years ago
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