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3 years ago

3 hundred thousand 3 thousand 8 hundred 4 tens

Mathematics

1 answer:

alekssr [168]3 years ago

3 0

Answer:

3384

Step-by-step explanation:

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Marianna martinez sells copy paper to local schools. SHE EARNS A 13 PERCENT STRAIGHT COMMISSION ON ALL SALES. IN NOVEMBER HER SA

aksik [14]

To solve this, you would take 13% of 28,540.
We can do this by multiplying 28,540 by .13 .
This give you the answer of a $3,710.20 commission.

Hope this helps.

7 0

3 years ago

The formula for converting a Celsius temperature to a Fahrenheit temperature is: F = C × 9⁄5 + 32 If C = 100 degrees, what is th

zmey [24]

F = 1.8C + 32
F = 1.8(100) + 32
F = 180 + 32
F = 212 degrees

7 0

3 years ago

Can you guys show me what buttons do I press for 3/4 + 1/6 on a TI-84 calculator?

antiseptic1488 [7]

Answer:

(3/4)+(1/6)

Step-by-step explanation:

put fractions in quotations

5 0

3 years ago

You buy a new laptop for $300$300. The sales tax is 6%6%. What is the total cost for the laptop including the sales tax?

cricket20 [7]

Answer:

Cost Including tax would be $318

Step-by-step explanation:

Given:

Price of laptop = $300

Sales tax = 6% of price

To Find:

Cost with tax = ?

Solution:

Cost with tax = Price of laptop + Value of tax

We have to find the value of tax

Value of tax = 6% of Price

putting the value

Value of tax = 6 % * $300

$=\frac{6}{100}*300$

= $18

Now Cost with tax = Price of laptop + Value of tax

Putting in the value

Cost with tax = 300 + 18

= $318

So Cost Including tax would be $318

6 0

3 years ago

Read 2 more answers

Todea what did one pencil say to another mathematics algebra order of operations answer

Serjik [45]

Part 1

$6- \frac{18-3^2}{4+(2-3)} =6- \frac{18-9}{4+(-1)} \\ \\ =6- \frac{9}{4-1} =6- \frac{9}{3} =6-3 \\ \\ =3$

Part 2

$7-8\div4(3^2-1)=7-8\div4(9-1) \\ \\ =7-8\div4(8)=7-8\div32=7- \frac{1}{2} \\ \\ =6 \frac{1}{2} = \frac{13}{2}$

Part 3

$2-2(2-5)^2+3^2=2-2(-3)^2+9 \\ \\ =2-2(9)+9=2-18+9=-7$

Part 4

$(5^2-9\cdot3)^2-11=(25-27)^2-11 \\ \\ =(-2)^2-11=4-11=-7$

Part 5

$[(2-3)^2-5]\cdot4=[(-1)^2-5]\cdot4 \\ \\ =(1-5)\cdot4=-4\cdot4=-16$

Part 6

$12-11\cdot2+16\div8=12-22+2 \\ \\ =-8$

Part 7

$-5+1\cdot3-(7-2^3)=-5+3-(7-8) \\ \\ =-2-(-1)=-2+1=-1$

Part 8

$8+2\cdot3-14\div7=8+6-2 \\ \\ =12$

Part 9

$(8-2)^2+\frac{1}{4}[4-3(6-10)]=6^2+\frac{1}{4}[4-3(-4)] \\ \\ =36+\frac{1}{4}[4-(-12)]=36+\frac{1}{4}(4+12)=36+\frac{1}{4}(16) \\ \\ =36+4=40$

Part 10

$7+(2-3^2)\cdot5=7+(2-9)\cdot5 \\ \\ =7+(-7)\cdot5=7+(-35)=7-35 \\ \\ =-28$

Part 11

$3-2[2^3+(-1)^3]=3-2[8+(-1)] \\ \\ =3-2(8-1)=3-2(7)=3-14 \\ \\ -11$

Part 12

$18+6\div3(2^2+5)=18+6\div3(4+5) \\ \\ =18+6\div3(9)=18+6\div27=18+ \frac{2}{9} \\ \\ =18 \frac{2}{9}$

8 0

3 years ago