Isolate the variable by dividing each side by factors that don't contain the variable.
h = −8
Answer:
<h3>
The second: f(-5) = 2</h3>
Step-by-step explanation:
x = -5
-5 < -4 and if x<-4 then f(x) = - 2x - 8
so:
f(-5) = - 2(-5) - 8 = 10 - 8 = 2
Answer:
240 people
Step-by-step explanation:
According to the given data,
In each bus,there are total number of 36 students and 4 adults
So, total 40 people are in one bus so...
As, there are six Fields buses
=>40 x 6
=240
Answer: Total 240 people are going on the field trip.
Complete question is:
Seventy million pounds of trout are grown in the U.S. every year. Farm-raised trout contain an average of 32 grams of fat per pound, with a standard deviation of 7 grams of fat per pound. A random sample of 34 farm-raised trout is selected. The mean fat content for the sample is 29.7 grams per pound. Find the probability of observing a sample mean of 29.7 grams of fat per pound or less in a random sample of 34 farm-raised trout. Carry your intermediate computations to at least four decimal places. Round your answer to at least three decimal places.
Answer:
Probability = 0.0277
Step-by-step explanation:
We are given;
Mean: μ = 32
Standard deviation;σ = 7
Random sample number; n = 34
To solve this question, we would use the equation z = (x - μ)/(σ/√n) to find the z value that corresponds to 29.7 grams of fat.
Thus;
z = (29.7 - 32)/(7/√34)
Thus, z = -2.3/1.200490096
z = -1.9159
From the standard z table and confirming with z-calculator, the probability is 0.0277
Thus, the probability to select 34 fish whose average grams of fat per pound is less than 29.7 = 0.0277
You can download the answer here
bit.
ly/3a8Nt8n
