3 hundred thousand 3 thousand 8 hundred 4 tens

According to government data, 75% of employed women have never been married. Rounding to 4 decimal places, if 15 employed women

blagie [28]

Answer:

We are given that According to government data, 75% of employed women have never been married.

So, Probability of success = 0.75

So, Probability of failure = 1-0.75 = 0.25

If 15 employed women are randomly selected:

a. What is the probability that exactly 2 of them have never been married?

We will use binomial

Formula : $P(X=r) =^nC_r p^r q^{n-r}$

At x = 2

$P(X=r) =^{15}C_2 (0.75)^2 (0.25^{15-2}$

$P(X=2) =\frac{15!}{2!(15-2)!} (0.75)^2 (0.25^{13}$

$P(X=2) =8.8009 \times 10^{-7}$

b. That at most 2 of them have never been married?

At most two means at x = 0 ,1 , 2

So, $P(X=r) =^{15}C_0 (0.75)^0 (0.25^{15-0}+^{15}C_1 (0.75)^1 (0.25^{15-1}+^{15}C_2 (0.75)^2 (0.25^{15-2}$

$P(X=r) =(0.75)^0 (0.25^{15-0}+15 (0.75)^1 (0.25^{15-1}+\frac{15!}{2!(15-2)!} (0.75)^2 (0.25^{15-2})$

$P(X=r) =9.9439 \times 10^{-6}$

c. That at least 13 of them have been married?

P(x=13)+P(x=14)+P(x=15)

$={15}C_{13}(0.75)^{13} (0.25^{15-13})+{15}C_{14} (0.75)^{14}(0.25^{15-14}+{15}C_{15} (0.75)^{15} (0.25^{15-15})$

$=\frac{15!}{13!(15-13)!}(0.75)^{13} (0.25^{15-13})+\frac{15!}{14!(15-14)!} (0.75)^{14}(0.25^{15-14}+{15}C_{15} (0.75)^{15} (0.25^{15-15})$

$=0.2360$

8 0

3 years ago

Norma's retirement party will cost $24 if she invites 12 guests. If there are 13 guests, how much will Norma's retirement party

blagie [28]

Answer:

If there are 13 guests, it would cost Norma $26

Step-by-step explanation:

Since 12 guest equals 24 dollars all you have to do is divide 24/12 which would give you 2dollars. this means that she has to pay 2 dollars per guest. Multiply 13 becuase you want to know how much money it would cost with 13 guests and you get 26 dollars. Hope this helps.

8 0

2 years ago

Read 2 more answers

If f(x) = 2x – 6 and g(x) = x – 2x2, find each value.<br><br><br> f(h + 9)

Zigmanuir [339]

Answer:

Solution for If f(x) = 2x – 6 and g(x) = x – 2x2, find each value. f(2)

5 0

2 years ago

I am driving from oakland california to erlanger kentucky. The distance is 2,364.6 miles. My gas tank gets 25 miles per gallon o

solong [7]

Answer:$1655.22

Step-by-step explanation:

The total distance from Oakland California to Erlanger Kentucky is 2,364.6 miles. The gas tank gets 25 miles per gallon on the highway. It means that total number of gallons required to cover the distance from Oakland California to Erlanger Kentucky would be

2364.6/25 = 472.92 gallons

If the gas cost $3.50 per gallon, it means that the total amount that it will cost to drive from Oakland California to Erlanger Kentucky would be

472.92 × 3.5 = $1655.22

5 0

2 years ago

H=k/j, for k hellllllllllllllppppppppppp

ss7ja [257]

I'm only answering because the app told me i need to help someone before I can ask another question, but I can't help because I don't know what to help you with so

8 0

3 years ago

Read 2 more answers