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babymother [125]
2 years ago
6

What is the solution to the inequality shown below? 2x - 9 -4 D .x > -5

Mathematics
2 answers:
coldgirl [10]2 years ago
7 0

Answer:

\boxed {\tt x

Step-by-step explanation:

The inequality given is:

2x-9 < -1

In order to solve the inequality, we must isolate the variable, x.

9 is being subtracted from 2x. The inverse of subtraction is addition. Add 9 to both sides of the equation.

2x-9+9 < -1+9

2x< -1+9

2x< 8

x is being multiplied by 2. The inverse of multiplication is division. Divide both sides of the equation by 2.

\frac{2x}{2}

x

x

The solution to the inequality is x<4

Elden [556K]2 years ago
4 0

Answer:

x < 4

Step-by-step explanation:

2x - 9 < - 1

Add 9 to each side

2x - 9+9 < - 1+9

2x < 8

Divide each side by 2

2x /2 < 8/2

x < 4

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Step-by-step explanation:

^^there are 20 Trucks in total  And 5 cars

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netineya [11]

Answer:

1895 x 906=

1,716,870

4 0
3 years ago
Please help me graph question
iogann1982 [59]

Answer:

Step-by-step explanation:

Put in the form of y = Ax + B

x + 2y = 10

2y = -x + 10

y = -½x + 5

has a slope of -½ and a y intercept of 5

-x + 4y = 8

4y = x + 8

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4 0
2 years ago
Find the range of the following piecewise function.
Anna11 [10]

Given:

The piecewise function is

f(x)=\begin{cases}x+4 & \text{ if } -4\leq x

To find:

The range of given piecewise function.

Solution:

Range is the set of output values.

Both functions f(x)=x+4 and f(x)=2x-1 as linear functions.

Starting value of f(x)=x+4 is at x=-4 and end value is at x=3.

Starting value: f(-4)=-4+4=0

End value: f(3)=3+4=7

Starting value of f(x)=2x-1 is at x=3 and end value is at x=6.

Starting value: f(3)=2(3)-1=5

End value: f(6)=2(6)-1=11

Least range value is 0 at x=-4 and 0 is included in the range because -4 is included in the domain.

Largest range value is 11 at x=6 and 11 is not included in the range because 6 is not included in the domain.

So, the range of the given piecewise function is [0,11).

Therefore, the correct option is A.

5 0
2 years ago
My Notes A large manufacturing plant uses lightbulbs with lifetimes that are normally distributed with a mean of 1600 hours and
Evgen [1.6K]

Answer:

The bulbs should be replaced each 1436.9 hours.

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

\mu = 1600, \sigma = 70

How often should the bulbs be replaced so that no more than 1% burn out between replacement periods?

This is the first percentile of hours. So it is X when Z has a pvalue of 0.01.

So it is X when Z = -2.33.

Z = \frac{X - \mu}{\sigma}

-2.33 = \frac{X - 1600}{70}

X - 1600 = -2.33*70

X = 1436.9

The bulbs should be replaced each 1436.9 hours.

6 0
3 years ago
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